如何在Objective-C中传递多个参数? [英] How do I pass multiple parameters in Objective-C?

问题描述

我已经阅读了几篇有关Objective-C方法语法的文章，但我想我不理解一个方法的多个名称.

I have read several of the post about Objective-C method syntax but I guess I don't understand multiple names for a method.

我正在尝试创建一个名为getBusStops的方法，该方法具有NSString和NSTimeInterval参数，返回类型为NSMutableArray.这就是我构造方法的方式，但显然在运行时会出错:

I'm trying to create a method called getBusStops with NSString and NSTimeInterval parameters and a return type of NSMutableArray. This is how I have constructed the method but it obviously gets errors at runtime:

- (NSMutableArray *)getBusStops:(NSString *)busStop
                                (NSTimeInterval *)timeInterval;

我看到了另一个带有方法的示例:

I saw another example with a method:

-(NSInteger)pickerView:(UIPickerView *)pickerView
            numberOfRowsInComponent:(NSInteger)component

我不明白为什么该方法每个参数都有一个方法名称.我应该对类似的东西做同样的事情吗?

I don't understand why this method has a method name for each parameter. Should I do the same with something like:

- (NSMutableArray *)getBusStops:(NSString *)busStop
                        forTime:(NSTimeInterval *)timeInterval

推荐答案

Objective-C没有命名参数，因此冒号左侧的所有内容都是方法名称的一部分.例如，

Objective-C doesn't have named parameters, so everything on the left side of a colon is part of the method name. For example,

getBusStops: forTime:

是方法的名称.该名称已分解，因此可以更具描述性.您可以简单地命名您的方法

is the name of the method. The name is broken up so it can be more descriptive. You could simply name your method

getBusStops: :

但这并不能告诉您有关第二个参数的很多信息.

but that doesn't tell you much about the second parameter.

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