如果在python中出现条件，如何避免多个单位? [英] How to avoid multiple flat if conditions in python?

问题描述

考虑代码段:

def check_conditions(range_of_numbers):
#method returns a list containing messages 
    list1 = []
    if condition1:
       list1.append("message1")
    if condition2:
       list1.append("message2")
    if condition3:
       list1.append("message3")
    try:
       for i in range_of_numbers:
           int(i)
    except ValueError:
        list1.append("message4")
    return message

仅当满足条件时，我才希望在with消息中有一个列表.我不使用多个if，因为它增加了代码的复杂性，并且每次添加新参数时，我最终都会添加新的if条件.

I want to have a list in the with messages only if the conditions were satisfied. I do not use multiple if's since it adds on to the code complexity and every time a new parameter is added I would end up adding a new if condition.

推荐答案

仅对条件/消息对进行循环:

just loop on the condition/message couples for instance:

for condition,message in ((condition1,"message1"),(condition2,"message2"),(condition3,"message3")):
    if condition:
       list1.append(message)

如果条件是排他性的，请考虑在一个条件匹配的情况下添加break.

if the conditions are exclusive, consider adding a break if one condition matches.

列表理解版本(虽然更"pythonic"，但在首次条件匹配时无法中断):

list comprehension version (more "pythonic" but not possible to break on first condition match, though):

list1 = [message for condition,message in ((condition1,"message1"),(condition2,"message2"),(condition3,"message3")) if condition]

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