使用语言环境查找字符串中的子字符串 [英] Find substring in string using locale

问题描述

我需要查找字符串是否包含子字符串，但要根据当前语言环境的规则.

I need to find if a string contains a substring, but according to the current locale's rules.

因此，如果我要搜索字符串"aba"，则使用西班牙语语言环境"cabalgar"，rábano"和gabán"将全部包含它.

So, if I'm searching for the string "aba", with the Spanish locale, "cabalgar", "rábano" and "gabán" would all three contain it.

我知道我可以将字符串与语言环境信息(整理)进行比较，但是是否有任何内置或starforforward方法可以对find执行相同操作，还是我必须编写自己的方法?

I know I can compare strings with locale information (collate), but is there any built-in or starightforward way to do the same with find, or do I have to write my own?

我可以很好地使用std :: string(最高TR1)或MFC的CString

I'm fine using std::string (up to TR1) or MFC's CString

推荐答案

作为参考，以下是使用通过ICU后端编译的boost语言环境的实现:

For reference, here is an implementation using boost locale compiled with ICU backend:

#include <iostream>
#include <boost/locale.hpp>

namespace bl = boost::locale;

std::locale usedLocale;

std::string normalize(const std::string& input)
{
    const bl::collator<char>& collator = std::use_facet<bl::collator<char> >(usedLocale);
    return collator.transform(bl::collator_base::primary, input);
}

bool contain(const std::string& op1, const std::string& op2){
    std::string normOp2 = normalize(op2);

    //Gotcha!! collator.transform() is returning an accessible null byte (\0) at
    //the end of the string. Thats why we search till 'normOp2.length()-1'
    return  normalize(op1).find( normOp2.c_str(), 0, normOp2.length()-1 ) != std::string::npos;
}

int main()
{
    bl::generator generator;
    usedLocale = generator(""); //use default system locale

    std::cout << std::boolalpha
                << contain("cabalgar", "aba") << "\n"
                << contain("rábano", "aba") << "\n"
                << contain("gabán", "aba") << "\n"
                << contain("gabán", "Âbã") << "\n"
                << contain("gabán", "aba.") << "\n"
}

输出:

true
true
true
true
false

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