为什么自定义对话框按钮没有在Android平台 [英] Why custom dialog box button is not working in android

问题描述

我们已经创建了两个自定义对话框，一个是关于，另一个是警报。当我在那个时候拖自定义对话框交替选择按钮不起作用。

We have creating two custom dialog box, one is about and another one is alert. When i choose alternately in the tow custom dialog box at that time the button is not working.

样code

AlertDialog.Builder builder;
Context mContext;
LayoutInflater inflater;
View layout;
Dialog dialog;
@Override
protected Dialog onCreateDialog( int id ) 
{ 
    switch ( id ) 
    {
        case 1:
            builder = null;
            mContext = this;
            inflater = ( LayoutInflater ) mContext.getSystemService( LAYOUT_INFLATER_SERVICE );
            layout = inflater.inflate( R.layout.alert_page, ( ViewGroup ) findViewById( R.id.alert_Root ) );
            Button alertUser = ( Button ) layout.findViewById( R.id.alert_Submit );
            alertUser.setOnClickListener( new View.OnClickListener()
            {
                public void onClick( View v )
                {
                    try
                    {
                        dialog.dismiss();
                    }
                    catch ( Exception e ) 
                    {
                        Toast.makeText( getBaseContext(), e.getMessage(), Toast.LENGTH_SHORT ).show();
                    }
                }
            });
            builder = new AlertDialog.Builder( mContext );
            builder.setView( layout );
            dialog = builder.create();
            dialog.show();
            break;

        case 2:
            builder = null;
            mContext = this;
            inflater = ( LayoutInflater ) mContext.getSystemService( LAYOUT_INFLATER_SERVICE );
            layout = inflater.inflate( R.layout.about_page, ( ViewGroup ) findViewById( R.id.about_Root ) );
            Button aboutUser = ( Button ) layout.findViewById( R.id.about_Submit );
            aboutUser.setOnClickListener( new View.OnClickListener()
            {
                public void onClick( View v )
                {
                    Log.e("About","About");
                    try
                    {
                        Log.e("About1","About");
                        dialog.dismiss();
                    }
                    catch ( Exception e ) 
                    {
                        Log.e("About","About12");
                        Toast.makeText( getBaseContext(), e.getMessage(), Toast.LENGTH_SHORT ).show();
                    }
                }
            });
            builder = new AlertDialog.Builder( mContext );
            builder.setView( layout );
            dialog = builder.create();
            dialog.show();
            break;
    }
    return dialog;
}

例如我正在使用两个按钮。第一个按钮叫案例1 和第二个按钮被称为 2的情况下。

For example i am using two button. First button is called case 1 and second button is called case 2.

我选择的第一个按钮访问案例1 然后再选择自定义对话框 alertUser 按钮成功退出对话框。

I am selected First button to access case 1 and then selected custom dialog box alertUser button successfully Exit the dialog box.

随即我选择第二个按钮访问案例2 ，然后选择自定义对话框 aboutUser 按钮成功退出对话框。

Immediately I am selected Second button to access case 2 and then select custom dialog box aboutUser button successfully Exit the dialog box.

刚结束后，我选择的第一个按钮访问案例1 ，然后选择自定义对话框 alertUser 按钮现在对话框中不存在（现在的按钮不工作）。

After Immediately I am selected First button to access case 1 and then select custom dialog box alertUser button Now the dialog box does not exist (button is now not working).

我在哪里错了code。如何解决这个问题。

Where i am mistaken code. How do solved this problem.

先谢谢了。

推荐答案

您呼叫对话框，的ShowDialog（INT）。删除此行 dialog.show（）; 在 onCreateDialog

you are calling dialog as showDialog(int). remove this line dialog.show(); in your onCreateDialog

和呼叫 dismissDialog（INT）来关闭该对话框，而不是 dialog.dismiss（）;

and call dismissDialog(int) to dismiss the dialog instead of dialog.dismiss();

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