在PHP中检测MIME类型失败 [英] Detecting a mime type fails in php
问题描述
我有以下PHP代码显示了上传文件的mime类型.
I have the following PHP code that shows the mime type of an uploaded file.
<?php
if ($_POST) {
var_dump($_FILES);
$finfo = new finfo(FILEINFO_MIME_TYPE);
var_dump($finfo->file($_FILES['file']['tmp_name']));
} else{
?>
<form method="POST" enctype="multipart/form-data"><input name="file" type="file"><input name="submit" value="send" type="submit"/></form>
<?php
}
使用此脚本上传somefile.csv的结果如下.
The result of uploading somefile.csv with this script is as follows.
array (size=1)
'file' =>
array (size=5)
'name' => string 'somefile.csv' (length=12)
'type' => string 'text/csv' (length=8)
'tmp_name' => string '/tmp/phpKiwqtu' (length=14)
'error' => int 0
'size' => int 3561
string 'text/x-fortran' (length=14)
因此,MIME类型当然应该是text/csv.但是我使用的框架(Symfony 1.4)将这种方法与fileinfo一起使用.
So of course the mime type should be text/csv. But the framework I use (Symfony 1.4) uses the method with fileinfo.
我还进行了进一步测试,似乎命令(在Ubuntu上)file --mime-type somefile.csv
返回somefile.csv: text/x-fortran
,命令mimetype somefile.csv
返回somefile.csv: text/csv
. somefile.csv是使用MSOffice创建的(我不知道这是否重要).
显然mimetype
使用了一些很棒的mime数据库( http://freedesktop.org/wiki/Software /shared-mime-info ),而file
则没有.
Also I tested a little further it seems that the command (on Ubuntu) file --mime-type somefile.csv
returns somefile.csv: text/x-fortran
and the command mimetype somefile.csv
returns somefile.csv: text/csv
. somefile.csv is created with MSOffice (I don't know if this matters).
Apparently mimetype
uses some awesome mime database (http://freedesktop.org/wiki/Software/shared-mime-info), while file
does not.
- PHP是否使用
file
或mimetype
还是都不使用? - 此外,我不确定该怎么做;我上传的文件格式错误?我必须使用其他的mime数据库吗? PHP被窃听了吗?这是怎么回事?
- Does PHP use
file
ormimetype
or neither? - Further, I am not sure what to do here; is my uploaded file wrongly formatted? Do I have to use a different mime database? Is PHP bugged? What is going on here?
edit:
将其检测为fortran程序的原因是somefile.csv仅包含以下内容:
The reason why it is detected as a fortran program is because somefile.csv contains only the following:
somecolumn;
C F;
我认为CSV文件的上述内容有效吗?如果一个字段包含空格,则不必将该字段放在引号内,对吗?
I believe the above contents of a CSV file is valid right? If a field contains a space this field does not have to be put inside quotes, right?
推荐答案
我在这里没有Unix框可以检查真实的魔术"文件(用于猜测MIME类型的签名数据库),但是Google进行了快速搜索这个:
I don't have a Unix box here to inspect a real "magic" file (the signatures database used to guess mime types) but a quick Google search revealed this:
# $File: fortran,v 1.6 2009/09/19 16:28:09 christos Exp $
# FORTRAN source
0 regex/100 \^[Cc][\ \t] FORTRAN program
!:mime text/x-fortran
显然,它扫描文件的开头以查找以单个C字母加空格开头的行,这似乎是
Apparently, it scans the start of the file looking for lines that begin with a single C letter plus spaces, which seem to be a Fortran style comment. Thus the false positive:
somecolumn;
C F;
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