MIPS(或SPIM):加载浮点数 [英] MIPS (or SPIM): Loading floating point numbers

问题描述

我正在尝试使用一些小型编译器，同时尝试在此处学习一些MIPS.这是我的问题:

I am working on a little mini compiler while trying to learn some MIPS here. Here's my issue:

MIPS的li指令(立即加载)会像这样

MIPS has an instruction li (load immediate) which would work like this

li $5,100

这会将100加载到寄存器5中.

which would load 100 into register 5.

但是，我现在需要将浮点数加载到寄存器中，并且正在努力寻找一种方法来做...因为$ 5,2.5的li无效.

However, I need to load floats into registers right now and am struggling with figuring out a way to do it...since li $5,2.5 does not work.

有人有什么建议吗?

我正在C语言中工作，我想我可以以某种方式获取正在使用的float的整数表示形式(即，float二进制表示== ints二进制表示)，然后将整数"加载到寄存器中并从那时起就把它当作浮游物来对待.

I am working in C, I was thinking I could somehow get the integer representation of the float I am working with (i.e. so the floats binary representation == the ints binary representation) then load the "integer" into the register and treat it like a float from then on.

也许为时已晚，但我现在停滞了.

Maybe its too late but Im stuck right now.

推荐答案

您将需要使用浮点寄存器来加载浮点数.

You will need to use the floating point registers to load your floats.

代替:

li $5,2.5

尝试:

li.s $f5,2.5

看看在整数和浮点寄存器之间移动的mfc1和mtc1指令.

Take a look at mfc1 and mtc1 instructions to move between integer and floating point registers.

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