Typemock隔离器:模拟未注入的依赖项? [英] Typemock Isolator: Mock a dependency that's not injected?

问题描述

我的WidgetDoer类取决于未注入的Foo.我需要伪造_foo的DoStuffWith()实现(然后确认Do()返回了结果-这是我的真实代码的简化表示).

My WidgetDoer class depends on Foo, which is not injected. I need to fake _foo's implementation of DoStuffWith() (and then verify that Do() returned the result -- this is a simplified representation of my real code).

public class WidgetDoer {
    readonly Foo _foo;

    public WidgetDoer() {
        _foo = new Foo();
    }

    public Bar Do(Widget widget) {
        var result = _foo.DoStuffWith(widget);
        return result;
    }
}

我试图使用以下隔离器语法来防止创建真正的Foo对象(在WidgetDoer()构造函数内部)，但是无论如何都将实例化真正的Foo对象:

I tried to use the following Isolator syntax to prevent a real Foo object from being created (inside the WidgetDoer() constructor), but the real Foo object is instantiated anyway:

var fooFake = Isolate.Fake.Instance<Foo>();
Isolate.WhenCalled(() => new Foo()).WillReturn(fooFake);

我可以使用Typemock模拟未注入的依赖项吗?

Can I use Typemock to mock a dependency which is not injected?

推荐答案

此代码使我可以模拟耦合的依赖项:

This code allowed me to mock the coupled dependency:

Isolate.Swap.NextInstance<Foo>().With(FooFake);

请记住， TypeMock支持mscorlib中很少的类型.

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