迅速解散模态并推送到新的VC [英] swift dismiss modal and push to new VC

问题描述

我有tableview ... 1个表，显示一个新的模式窗口，当我按下按钮时，我想关闭模式窗口并按下VC.我的代码仅隐藏模式视图，但不进行推送.

I have tableview... 1 table showing a new modal window and when I press the button I want to dismiss the modal window and push to VC. My code only hide the modal view but no push is made.

    @IBAction func registrationBtn(sender: AnyObject) {

    let openNewVC = self.storyboard?.instantiateViewControllerWithIdentifier("registrationVcID") as! RegistrationVC

    self.dismissViewControllerAnimated(false, completion: { () -> Void   in
         self.navigationController?.pushViewController(openNewVC, animated: true)

            })
}

推荐答案

您应该创建一个协议

protocol View1Delegate: class {
    func dismissViewController(controller: UIViewController)
}

当您点击注册"上的按钮时，将把代表回叫到TableView. TableViewController应该实现:

When you tap button on Register will call delegate back to TableView. TableViewController should implement:

  func dismissViewController(controller: UIViewController) {
    controller.dismissViewControllerAnimated(true) { () -> Void in
        //Perform segue or push some view with your code

    }
}

您可以在这里做任何事情.推送您想要的屏幕.您可以查看我的演示的详细工具:在Swift中进行演示推送视图

You can do anything in here. Push screen you want. Detail implement you can see my demo: Demo Push View in Swift

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