Python中的六角形自组织图 [英] Hexagonal Self-Organizing map in Python

问题描述

我正在寻找六角形 自组织地图在Python上.

I am looking for hexagonal self-organizing map on Python.

1. 就绪模块.如果存在的话.
2. 绘制六角形细胞的方式
3. 与六角形单元格作为数组或其他元素一起使用的算法

关于: 自组织图(SOM)或自组织特征图(SOFM)是一种人工神经网络，使用无监督学习对其进行训练，以生成低维(通常为二维)

About: A self-organizing map (SOM) or self-organizing feature map (SOFM) is a type of artificial neural network that is trained using unsupervised learning to produce a low-dimensional (typically two-dimensional)

推荐答案

我没有关于第1点的答案，但是有关于第2点和第3点的一些提示.但是一个具有6个邻居的图块的概念空间.可以用排列成列的正方形瓷砖进行建模，其中奇数列垂直移动一个正方形大小的一半.我将尝试一个ASCII图:

I don't have an answer for point 1, but some hints for point 2 and 3. In your context, you're not modelling a physical 2D space but a conceptual space with tiles that have 6 neighbors. This can be modelled with square tiles arranged in columns with the odd colums shifted vertically by half the size of a square. I'll try an ASCII diagram:

 ___     ___     ___     
|   |___|   |___|   |___
|___|   |___|   |___|   |
|   |___|   |___|   |___|
|___|   |___|   |___|   |
|   |___|   |___|   |___|
|___|   |___|   |___|   |
    |___|   |___|   |___|

您可以轻松地看到每个正方形都有6个邻居(当然，边缘上的邻居除外).可以很容易地将其建模为2D正方形数组，并且计算位置(i，j)处正方形的坐标的规则非常简单:

You can see easily that each square has 6 neighbors (except the ones on the edges of course). This gets easily modeled as a 2D array of squares, and the rules to compute the coordinates of the square at at position (i, j), i being the row and j the column are quite simple:

如果j是偶数:

(i+1, j), (i-1, j), (i, j-1), (i, j+1), (i-1, j-1), (i+1, j-1)

如果j为奇数:

(i+1, j), (i-1, j), (i, j-1), (i, j+1), (i+1, j-1), (i+1, j+1)

(前四个词是相同的)

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