如何找到从Python导入函数的位置? [英] How to find where a function was imported from in Python?

问题描述

我有一个带有功能的Python模块:

I have a Python module with a function in it:

  == bar.py ==
  def foo(): pass
  == EOF ==

然后将其导入到全局名称空间中，如下所示:

And then I import it into the global namespace like so:

from bar import *

所以我现在可以使用功能foo.如果我打印出来:

So now the function foo is available to me. If I print it:

print foo

译员愉快地告诉我:

 <function foo at 0xb7eef10c>

在这一点上，我是否有办法找出功能foo来自模块bar?

Is there a way for me to find out that function foo came from module bar at this point?

推荐答案

foo.__module__应该返回bar

如果您需要更多信息，可以从sys.modules['bar']获取它，它的__file__和__package__属性可能很有趣.

If you need more info, you can get it from sys.modules['bar'], its __file__ and __package__ attributes may be interesting.

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