带有负数的Ruby模3是不直观的 [英] Ruby modulo 3 with negative numbers is unintuitive
问题描述
带有负数的Ruby模数规则尚不清楚.在IRB中:
Ruby modulo rules with negative numbers are unclear. In IRB:
-7 % 3 == 2
应该是1
!
为什么?
推荐答案
当%
的操作数之一为负数时,没有明确的最佳答案
返回什么结果.每种编程语言都有其自己的规则.
Wikipedia页面上的 Modulo操作有一个庞大的表格
每种编程语言都已决定要解决此问题,目前尚无明确的方法
共识:
When one of the operands to %
is negative, there’s no clear best answer
for what result to return. Every programming language has its own rules.
The Wikipedia page for Modulo operation has a giant table of how
each programming language has decided to handle this, and there’s no clear
consensus:
$ # Modulus sign is:
$
$ curl 'http://en.wikipedia.org/w/index.php?title=Modulo_operation&action=edit§ion=1' \
| egrep -o 'Divisor|Dividend|Always positive|Closest to zero|Not defined|Implementation defined' \
| sort | uniq -c | sort -nr
67 Dividend
42 Divisor
7 Always positive
4 Closest to zero
2 Not defined
2 Implementation defined
有些选择左操作数的符号,有些选择右操作数 操作数.其他人未指定.例如, C编程语言 说:
Some choose the sign of the left-hand operand, and some the right-hand operand. Others don’t specify. For example, The C Programming Language says:
对于负操作数,%[结果]的符号取决于机器.
the sign of the result for % [is] machine-dependent for negative operands
C并没有为如何处理这一问题做出特定选择,而只是 返回所使用的特定硬件或编译器选择的内容 实施!这似乎已经在较新的版本中进行了标准化 C编程语言标准.
Instead of making a particular choice for how to handle this, C just returns whatever the particular hardware or compiler being used have chosen to implement! This seems to have been standardized in more recent versions of the C programming language standards.
如果要在Ruby中获得特定版本,则有两种不同的方法
您可以调用的方法 modulo
aka %
和 remainder
,
在负数上具有不同的行为:
If you want to get a particular version in Ruby, there are two different
methods you could call, modulo
aka %
, and remainder
,
with different behaviour on negative numbers:
$ irb
irb(main):001:0> -7.modulo(3)
=> 2
irb(main):002:0> -7.remainder(3)
=> -1
在其他没有内置方法的语言中,您可能会结束
两次使用%
来获得所需的符号.
In other languages that don’t have built-in methods for this, you may end
up using %
twice to get the desired sign.
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