MongoDB按数组字段中的值分组 [英] MongoDB group by values in an array field

问题描述

我的资产文件采用以下格式.

I have my asset documents in the below format.

db.asset.find({}).limit(1).pretty()
{
    "_id" : ObjectId("54e650a10364a65f62c0df4a"),
    "_class" : "com.model.core.Asset",
    "displayName" : "Bingo Rhymes For Children + More 3D Animation Nursery Rhymes & Kids' Songs",
    "assetType" : "VIDEO",
    "active" : true,
    "originalUrl" : "https://www.youtube.com/watch?v=j-tdVvvXn9k&feature=youtube_gdata",
    "groupIds" : [ ],
    "folderIds" : [
        "54e6507b0364a65f62c0df47",
        "54e6507b0364a65f62c0df48"
    ]
}

如您所见，每个资产都可以具有与其关联的folderId的集合.如果我想与相关资产一起找到folderIds，mongo聚合查询将如何显示?本质上，我想按folderId对资产进行分组.

As you can see each asset can have a collection of folderId to which it is associated with. If I want to find the folderIds along with the associated assets how does the mongo aggregate query will look like? Essentially I want to group the assets by folderId.

推荐答案

首先，您需要按folderIds字段展开，而不是按_id分组，然后将资产_id推送到列表assets_id中. /p>

You first need to unwind by the folderIds field, than group by _id and push the asset _id into a list assets_id.

db.asset.aggregate([{$unwind:"$folderIds"},  {$group:{_id: "$folderIds",assets:{$push: {assets_id:"$_id"}}}}])

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