使用PyMongo的Concat阵列失败,原因是未知的组运算符'$ concatArrays' [英] Concat arrays using PyMongo failed with unknown group operator '$concatArrays'
问题描述
我有mongodb数据,例如:
I have mongodb data like:
{'word': 'good', 'info': [{'tbl_id': 'd1', 'term_freq': 2}, {'tbl_id': 'd2', 'term_freq': 56}, {'tbl_id': 'd3', 'term_freq': 3}]}
{'word': 'spark', 'info': [{'tbl_id': 'd1', 'term_freq': 6}, {'tbl_id': 'd3', 'term_freq': 11}, {'tbl_id': 'd4', 'term_freq': 10}]}
{'word': 'good', 'info': [{'tbl_id': 'd4', 'term_freq': 12}, {'tbl_id': 'd5', 'term_freq': 8}, {'tbl_id': 'd8', 'term_freq': 7}]}
{'word': 'spark', 'info': [{'tbl_id': 'd5', 'term_freq': 6}, {'tbl_id': 'd6', 'term_freq': 11}, {'tbl_id': 'd7', 'term_freq': 10}]}
我想使用pymongo对其进行处理,结果应为:
and I want to use pymongo to process it, the result should be:
{'word': 'good',
'info': [{'tbl_id': 'd1', 'term_freq': 2}, {'tbl_id': 'd2', 'term_freq': 56}, {'tbl_id': 'd3', 'term_freq': 3},
{'tbl_id': 'd4', 'term_freq': 12}, {'tbl_id': 'd5', 'term_freq': 8}, {'tbl_id': 'd8', 'term_freq': 7}]}
{'word': 'spark',
'info': [{'tbl_id': 'd1', 'term_freq': 6}, {'tbl_id': 'd3', 'term_freq': 11}, {'tbl_id': 'd4', 'term_freq': 10},
{'tbl_id': 'd5', 'term_freq': 6}, {'tbl_id': 'd6', 'term_freq': 11}, {'tbl_id': 'd7', 'term_freq': 10}]}
我在pymongo中使用组:
I use group in pymongo:
a = mycol.aggregate([{"$group": {"_id":"$word", 'infos': {"$concatArrays": 1}}}])
for i in a:
print(i)
它出错了:pymongo.errors.OperationFailure: unknown group operator '$concatArrays'
.
并且我使用group
关键字:
It went wrong: pymongo.errors.OperationFailure: unknown group operator '$concatArrays'
.
and I use group
keyword:
a = mycol.group(key='word',condition=None, initial={'infos': []}, reduce={"$concatArrays": "info"})
for i in a:
print(i)
它也出错了:
Traceback (most recent call last):File "F:/programs/SearchEngine/test.py", line 167, in <module> a = mycol.group(key='word',condition=None, initial={'infos': []}, reduce={"$concatArrays": "info"}) File "C:\Users\ll\.virtualenvs\SearchEngine\lib\site-packages\pymongo\collection.py", line 2550, in group group["$reduce"] = Code(reduce) File "C:\Users\ll\.virtualenvs\SearchEngine\lib\site-packages\bson\code.py", line 54, in __new__ "instance of %s" % (string_type.__name__))
TypeError: code must be an instance of str
推荐答案
收到此错误消息的原因是因为$concatArrays
运算符是 $ group累加器.
The reason you are getting this error message is because the $concatArrays
operator is an expression operator not a $group accumulator.
话虽如此,您可以使用以下管道进行此操作:
That being said, you can do this with the following pipeline:
[
{
"$group": {
"_id": "$word",
"info": {
"$push": "$info"
}
}
},
{
"$project": {
"_id": 0,
"word": "$_id",
"info": {
"$reduce": {
"input": "$info",
"initialValue": [
],
"in": {
"$concatArrays": [
"$$value",
"$$this"
]
}
}
}
}
}
]
我们在$group
阶段中使用$push
运算符创建 info 的二维列表,然后在另一个$project
阶段中,使用
We create a 2d list of info in the $group
stage with the $push
operator then in the another $project
stage you flatten the list using the $reduce
and $concatArrays
.
这篇关于使用PyMongo的Concat阵列失败,原因是未知的组运算符'$ concatArrays'的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!