Pymongo正则表达式$所有多个搜索词 [英] Pymongo Regex $all multiple search terms

问题描述

我想搜索MongoDB，以便仅获得在某个配置中在键中同时找到所有x的结果.

I want to search MongoDB so that I get only results where all x are found in some configuration together in the key.

collected_x =  ''
for x in input:
  collected_x = collected_x + 're.compile("' + x + '"), '
  collected_x_cut = collected_x[:-2]

cursor = db.collection.find({"key": {"$all": [collected_x_cut]}})

这不会带来预期的结果.如果我自己输入倍数x，它将起作用.

This does not bring the anticipated result. If I input the multiple x by themselves, it works.

cursor = db.collection.find({"key": {"$all": [re.compile("Firstsomething"), 
                                              re.compile("Secondsomething"),
                                              re.compile("Thirdsomething"), 
                                              re.compile("Fourthsomething")]}})

我在做什么错了?

推荐答案

您正在for循环中构建一个字符串，而不是re.compile对象的列表.您想要:

You are building a string in your for loop not a list of re.compile objects. You want:

collected_x = []                            # Initialize an empty list

for x in input:                             # Iterate over input
  collected_x.append(re.compile(x))         # Append re.compile object to list

collected_x_cut = collected_x[:-2]          # Slice the list outside the loop

cursor = db.collection.find({"key": {"$all": collected_x_cut}})

一种简单的方法是使用 map 进行构建列表:

A simple approach would be to use map to build the list:

collected = map(re.compile, input)[:-2]
db.collection.find({"key": {"$all": collected}})

或 list comprehension :

collected = [re.compile(x) for x in input][:-2]
db.collection.find({"key": {"$all": collected}})

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