如何在Lambda函数中使用python搜索Json输出中的匹配列表? [英] How to search matched list in Json output using python in lambda function?
问题描述
我有两个收藏集社区和个人资料.
I have two collections community and profile.
社区收集样本数据:
_id : ObjectId("5dc1f30abcafe70001bd0075")
communityname : "testing1",
user_id : ObjectId("5dc1f2ed4a59120001a4d09d")
active_flag : 0
_id : ObjectId("5dc1f30abcafe70001bd0082")
communityname : "testing1",
user_id : ObjectId("5dc4a8b7360a0100012d3ec8")
active_flag : 0
个人资料收集示例数据:
profile collection sample data:
_id : ObjectId("5dc1f2ed4a59120001a4d09d"),
username : "Haneesh",
"name" : "hani"
_id : ObjectId("5dc4a8b7360a0100012d3ec8"),
username : "Harish",
name : "Hari"
我在下面编写这样的lambda函数.
I write the lambda function like this below.
community =db.community
comm_id = ObjectId(event['c_id'])
user1 = list(community.aggregate([{
"$match" : { "_id" : comm_id }
},
{
"$lookup" : {
"from" : "profile",
"localField" : "user_id",
"foreignField" : "_id",
"as" : "details"
}
},
{ "$unwind" : "$details" },
{
"$project" : {
"_id" : 0,
"username" : "$details.username",
"name" : "$details.name"
}
}
]))
user2 = json.loads(json.dumps(user1, default=json_util.default))
return user2
我已经执行了lambda函数,我得到的输出如下:
I have executed the lambda function, I'm getting output like this below:
[
{
"username": "anvithpm026",
"name": "Anvith P M"
},
{
"username": "shailu",
"name": "shail"
},
{
"username": "sukumar",
"name": "suku"
}
]
现在,我担心的是如何搜索匹配列表.例如,如果一个字母与用户名匹配,则它将获得用户名和名称.我尝试使用正则表达式,但是没有用.请帮我解决.预先感谢.
Now my concern is, how to search matched list. Example if a letter matchs with the username, then it get the username along with name. I've tried to use the regular expression but it didn't work. Please help me with a solution. Thanks in advance.
推荐答案
需要细微调整才能完成工作,以下是查询:
A minor tweak does the job, below is the query :
user1 = list(community.aggregate([{
"$match": { "_id": ObjectId("5dc1f30abcafe70001bd0075") }
},
{
"$lookup": {
"from": "profile",
"localField": "user_id",
"foreignField": "_id",
"as": "details"
}
}, { "$unwind": "$details" }, { "$match": { "details.username": /eesh/i } }, {
"$project": {
"_id": 0,
"username": "$details.username",
"name": "$details.name"
}
}]))
请根据您的要求动态传递/eesh/i
.换句话说,我尝试在$lookup
本身中添加此过滤器{ "details.username": /eesh/i }
-这样我们就可以避免遵循$unwind
& $match
阶段,但是由于要检查两个过滤器-由于$match
的$expr
中使用regex
的限制很少,因此此查询为&甚至更容易做到.
Please pass /eesh/i
dynamically as per your requirement. In the other way I've tried to add this filter { "details.username": /eesh/i }
in $lookup
itself - that way we can avoid following $unwind
& $match
stages, But as we've two filters to be checked - due to few limitations on using regex
in $expr
of $match
, this query is the one & even this is easier to do.
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