猫鼬:如何更新所有符合条件的人? [英] Mongoose: how to update *all* persons matching a condition?

问题描述

我已经做过这样的事情(请原谅我对示例的愚蠢...:-):

I have do do something like this (please forgive me about the stupidity of the example... :-):

var dateRef = new Date(1990, 1, 1);
Person
  .where('dateOfBirth').gte(dateRef)
  .update({ $set: { isYoung: true } }, function (err, count) {
  })
;

即:对于每个出生日期(dateOfBirth)晚于参考日期的Person文档，我想将其设置为true字段isYoung.

I.e.: I'd like to $set to true field isYoung for every Person document whose date of birth (dateOfBirth) is later than a reference date.

即使(当前)有很多文档符合条件(所有年轻人，这里... :-)，我的代码也只适用于一个人.

My code is working for just one person, even if (currently) many documents do match the condition (all young people, here... :-).

有任何线索吗?

P.S .:作为奖励，如果可能的话，我也想将不匹配的人isYoung字段设置为false ...

P.S.: as a bonus, I'd like to set not-matching persons isYoung field to false, too, if possible...

推荐答案

您应该在更新中使用multi:true来更新多个文档，例如:

You should use multi:true in update to update multiple documents like :

var dateRef = new Date(1990, 1, 1);
Person
  .where('dateOfBirth').gte(dateRef)
  .update({ $set: { isYoung: true } },{multi: true}, function (err, count) {
  });

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