如何在控制台程序中获取鼠标位置? [英] How can I get the mouse position in a console program?

问题描述

如何在Windows控制台程序中的C ++中获得鼠标单击的位置? (一个变量，该变量在单击时返回鼠标的位置)

How can I get the mouse click position in C++ in a Windows console program? (A variable that returns the position of the mouse when clicked)

我想用简单的文本命令绘制菜单，因此当有人单击时，游戏会注册它并知道位置.我知道该怎么做，除了单击时能获得鼠标位置.

I want to draw a menu with simple text commands, so when someone clicks, the game will register it and know the position. I know how to do everything I need to do except get the mouse position when clicked.

推荐答案

您将需要使用 *ConsoleInput 系列方法(窥视，读取等).它们在控制台的输入缓冲区上运行，包括键盘和鼠标事件.总体策略是:

You'll need to use the *ConsoleInput family of methods (peek, read, etc). These operate on the console's input buffer, which includes keyboard and mouse events. The general strategy is:

1. 等待控制台的输入缓冲区句柄( ReadConsoleInput )
2. 确定等待事件的数量(lpNumberOfEventsRead)
3. 按您认为合适的方式处理它们(即MOUSE_EVENT和 MOUSE_EVENT_RECORD )

1. wait on the console's input buffer handle (ReadConsoleInput)
2. determine the number of waiting events (lpNumberOfEventsRead)
3. handle them as you see fit (i.e. MOUSE_EVENT and MOUSE_EVENT_RECORD)

您必须指出要使用首先，如本MSDN文章中所示.

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