使用PHP的LAME将WAV转换为MP3 [英] Convert WAV to MP3 using LAME from PHP

问题描述

我有WAV数据，我想使用PHP脚本将其实时转换为MP3. WAV文件起源于脚本，因此它不是作为文件开头的.

I have WAV data that I'd like to convert to MP3 on the fly with a PHP script. The WAV file originates with the script, so it does not start out as a file.

我可以运行以下命令:

exec( "lame --cbr -b 32k in.wav out.mp3" );

但这需要我先将in.wav写入磁盘，从磁盘中读出.mp3，然后在完成后进行清理.我不想这样做.相反，我将wav文件存储在$ wav中，我想通过LAME运行它，以便将输出的数据存储在$ mp3中.

But this will require that I first write in.wav to disk, read out.mp3 from disk, and then clean up when I'm finished. I'd prefer not to do that. Instead, I have the wav file stored in $wav, and I'd like to run this through LAME such that the outputted data is then stored in $mp3.

我已经看到了对FFMPEG PHP库的引用，但是如果可能的话，我宁愿避免为该任务安装任何其他库.

I've seen references to an FFMPEG PHP library, but I'd prefer to avoid having to install any additional libraries for this task if possible.

推荐答案

似乎proc_open()是我想要的.这是我编写和测试的代码片段，完全符合我的期望:

It appears that proc_open() is what I was looking for. Here's the snippet of code I wrote and tested that does exactly what I was looking for:

位置:

• $ wav是要转换的原始WAV数据.
• $ mp3保存转换后的MP3数据，

• $wav is the original WAV data to be converted.
• $mp3 holds the converted MP3 data,

$descriptorspec = array(
    0 => array( "pipe", "r" ),
    1 => array( "pipe", "w" ),
    2 => array( "file", "/dev/null", "w" )
);

$process = proc_open( "/usr/bin/lame --cbr -b 32k - -", $descriptorspec, $pipes );

fwrite( $pipes[0], $wav );
fclose( $pipes[0] );

$mp3 = stream_get_contents( $pipes[1] );
fclose( $pipes[1] );

proc_close( $process );

最终输出的数据与运行/usr/bin/lame --cbr -b 32k in.wav out.mp3的情况相同.

The final outputted data is identical to if I had run /usr/bin/lame --cbr -b 32k in.wav out.mp3.

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