JSON的Andr​​oid：JSON解析 [英] json android: parsing json

问题描述

我有一个JSON：

[ {user:"John",s:"Ldh",e:"usa"},{user:"Paul",s:"bukit panjang ",e:"FedExForum - Memphis"},{user:"ross",s:"bukit panjang ",e:"FedExForum - Memphis "}]

我用下面的code解析这个检索用户。

I am parsing this with the following code to retrieve all the values of "user" ..

public class ListViewAndroidActivity extends ListActivity {
private String newString, user;
ArrayList<String> results = new ArrayList<String>();
@Override
    public void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
TestServiceActivity test = new TestServiceActivity(); //This returns json from the server
   newString = test.readPooledFeed(); // returned json in string format

   JSONArray rootArray = new JSONArray(newString);
   int len = rootArray.length();
   for(int i = 0; i < len; ++i) {
       JSONObject obj = rootArray.getJSONObject(i);

      user = obj.optString("user");
    results.add(user);
   }
}

这让我没有错误..但没有显示在屏幕上..好心帮！

This gives me no error.. but nothing is shown on the screen .. kindly help!

推荐答案

optString：获取与键关联一个可选的字符串

optString : Get an optional string associated with a key.

我不明白你的JSON对象的关键 U ，它不应该是用户= obj.optString（用户） ;

I don't see the key u in your JSON object, shouldn't it be user = obj.optString("user");

这篇关于JSON的Andr​​oid：JSON解析的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！