如何避免这种Access SQL冲突? [英] How can I avoid this Access SQL kludge?
本文介绍了如何避免这种Access SQL冲突?的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
目标是从每个资格"的最新任务中返回信息.如果有两个具有相同日期的作业,则每个资格"仍只返回一行,并且所选择的作业是任意的.
The goal is to return the info from the latest assignment for each 'eligibility'. If there are two assignments with the same date, still only return one row per 'eligibility' with the assignment picked being arbitrary.
当前方法:
qCurrentAssignment_sub:
qCurrentAssignment_sub:
SELECT tblAssignment.EligibilityID, Max(DateAdd("s",[AssignmentID] Mod 10000,[AssignmentDate])) AS DatePlusIDMod10000
FROM tblAssignment
GROUP BY tblAssignment.EligibilityID;
qCurrentAssignment:
qCurrentAssignment:
SELECT tblAssignment.AssignedTo, tblAssignment.AssignedBy, tblAssignment.Method, tblAssignment.AssignmentDate
FROM qCurrentAssignment_sub INNER JOIN tblAssignment ON
(qCurrentAssignment_sub.EligibilityID = tblAssignment.EligibilityID) AND
(qCurrentAssignment_sub.DatePlusIDMod10000 = DateAdd("s",[AssignmentID] Mod 10000,[AssignmentDate]));
推荐答案
评论已更新
如果给出
- 每个工作分配ID都有多个工作分配
- 您要让assignid与最大的assignmentDate相关联
- 如果max(assignmentDate)存在一个以上的assignmentid,那么您想要最大的assignid
将qCurrentAssignment_sub更改为
Change qCurrentAssignment_sub to
qCurrentAssignment_sub
qCurrentAssignment_sub
SELECT
eligibilityid,
MAX(assignmentid) assignmentid
FROM
tblassignment
INNER JOIN
(SELECT tblassignment.eligibilityid,
MAX(AssignmentDate) AssignmentDate
FROM tblassignment
GROUP BY tblassignment.eligibilityid) maxAssignmentDate
ON tblassignment.eligibilityid = maxAssignmentDate.eligibilityid
and maxAssignmentDate.AssignmentDate = maxAssignmentDate.AssignmentDate
GROUP BY
eligibilityid
然后在assignmentid上重新加入到tblassignment.这也使连接更加干净
Then join back to tblassignment on assignmentid. This makes the join a little cleaner as well
qCurrentAssignment
qCurrentAssignment
SELECT tblassignment.assignedto,
tblassignment.assignedby,
tblassignment.method,
tblassignment.assignmentdate
FROM tblassignment
INNER JOIN qcurrentassignment_sub
ON tblassignment.assignmentid = qcurrentassignment_sub.assignmentid
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