如何将文件复制并重命名为输出文件夹作为构建的一部分 [英] How to copy and rename file to output folder as part of build

问题描述

我认为这更多是与msbuild有关的问题. 有一个.net核心应用程序，我需要有条件地发布文件，并根据Visual Studio 2019中选择的生成配置，在发布到目标之前应重命名该文件.

I believe this is more of an msbuild-related question. Have a .net core app and I need to conditionally publish a file and based on the build config selected in Visual Studio 2019, the file should be renamed before publishing to the target.

因此，我正在考虑修改csproj文件(除了msbuild文件本身之外，什么都没有) 我在复制任务上看不到条件选项 https://docs.microsoft.com/zh-cn/visualstudio/msbuild/copy-task?view = vs-2019

So Im looking at modifying the csproj file (which is nothing but an msbuild file itself) I dont see a condition option on the copy task https://docs.microsoft.com/en-us/visualstudio/msbuild/copy-task?view=vs-2019

我追求的目标是，如果我有3个不同的文件
tester-notes.dev.json tester-notes.debug.json tester-notes.prod.json

The goal Im after, is if I have 3 different files
tester-notes.dev.json tester-notes.debug.json tester-notes.prod.json

如果选择prod作为构建配置，我希望发布的文件为tester-notes.prod.json，但重命名为tester-notes.json

If prod is selected as a build config, I want the file published to be tester-notes.prod.json, but renamed to tester-notes.json

推荐答案

假设开发时在解决方案资源管理器中有三个文件(生成操作=无):

Assuming you have three files(build action = None) in Solution Explorer when developing:

如果您使用的是FileSystem发布模式，则可以使用与此脚本类似的方法来重命名并复制到发布文件夹:

You can use something similar to this script to rename and copy to publish folder if you're using FileSystem publish mode:

<ItemGroup Condition="$(Configuration)=='Dev'">
    <FileToRename Include="$(ProjectDir)\tester-notes.dev.json" />
  </ItemGroup>
  <ItemGroup Condition="$(Configuration)=='Debug'">
    <FileToRename Include="$(ProjectDir)\tester-notes.debug.json" />
  </ItemGroup>
  <ItemGroup Condition="$(Configuration)=='Prof'">
    <FileToRename Include="$(ProjectDir)\tester-notes.prof.json" />
  </ItemGroup>

  <Target Name="DoSthAfterPublish1" AfterTargets="Publish" Condition="$(Configuration)=='Dev'">
    <Copy SourceFiles="@(FileToRename)" DestinationFiles="@(FileToRename->Replace('.dev.json','.json'))"/>
    <Move SourceFiles="$(ProjectDir)\tester-notes.json" DestinationFolder="$(PublishDir)" OverwriteReadOnlyFiles="true"/>
  </Target>

  <Target Name="DoSthAfterPublish2" AfterTargets="Publish" Condition="$(Configuration)=='Debug'">
    <Copy SourceFiles="@(FileToRename)" DestinationFiles="@(FileToRename->Replace('.debug.json','.json'))"/>
    <Move SourceFiles="$(ProjectDir)\tester-notes.json" DestinationFolder="$(PublishDir)" OverwriteReadOnlyFiles="true"/>
  </Target>

  <Target Name="DoSthAfterPublish3" AfterTargets="Publish" Condition="$(Configuration)=='Prof'">
    <Copy SourceFiles="@(FileToRename)" DestinationFiles="@(FileToRename->Replace('.prof.json','.json'))"/>
    <Move SourceFiles="$(ProjectDir)\tester-notes.json" DestinationFolder="$(PublishDir)" OverwriteReadOnlyFiles="true"/>
  </Target>

如果将tester-notes.debug.json重置为tester-notes.Debug.json，则可以使用DestinationFiles="@(FileToRename->Replace('.$(Configuration).json','.json'))"将三个目标组合为一个.希望它能有所帮助:)

And if you can reset tester-notes.debug.json to tester-notes.Debug.json,, then we may combine the three targets into one by using DestinationFiles="@(FileToRename->Replace('.$(Configuration).json','.json'))". Hope it makes some help :)

此外:

根据Intellisense，我们可以找到Copy task支持Condition:

According to the Intellisense we can find the Copy task supports Condition:

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