优化查找和替换MS-Word VBA脚本 [英] Optimizing Find and Replace MS-Word VBA Script
问题描述
我编写了一个宏,用于替换三个空格中的第一个空格的格式,后跟一个带有蓝色字体的数字的特定字符串,另一个用于替换括号内的空格,后跟一个特定的字符串.
I wrote a macro for replacing the format of the first of three spaces followed by a certain string with a digit in blue font and another one for replacing the space inbetween brackets followed by a certain string.
您知道如何优化这两个过程吗(我使用MS-Word的搜索和替换对话框的通配符,但是猜想在VBA中使用它是很尴尬的..)
Do you know how to optimize these two procedures (I use wildcards of the search and replace dialogue of the MS-Word but guess it is rather awkard to use this in VBA..)?
我的宏:
Sub replace_3spaces()
Dim str_after As String
Dim re_number As Integer
str_after = "normal"
re_number = "1"
Selection.Find.ClearFormatting
Selection.Find.Replacement.ClearFormatting
With Selection.Find
.Text = "([^s]{3})" & "(" & str_after & ")"
.Replacement.Text = "§§§\2"
.Forward = True
.Wrap = wdFindContinue
.Format = False
.MatchCase = False
.MatchWholeWord = False
.MatchAllWordForms = False
.MatchSoundsLike = False
.MatchWildcards = True
End With
Selection.Find.Execute Replace:=wdReplaceAll
Selection.Find.ClearFormatting
Selection.Find.Replacement.Font.ColorIndex = wdBlue
With Selection.Find
.Text = "§§§"
.Replacement.Text = re_number & " "
.Forward = True
.Wrap = wdFindContinue
.Format = True
.MatchCase = False
.MatchWholeWord = False
.MatchAllWordForms = False
.MatchSoundsLike = False
.MatchWildcards = True
End With
Selection.Find.Execute Replace:=wdReplaceAll
End Sub
推荐答案
我不确定您要执行的操作,因为您的代码确实有效.当您说优化时,您是在问是否有一种更快的方法,还是在问是否可以缩短您的代码?我看不到您在开始时设置尺寸的任何原因,因此,如果您只是在寻找较短的代码,则可以使用以下代码:
I'm not entirely sure what you're trying to do because your code does work. When you say optimize, are you asking if there's a quicker way to do it, or are you asking if your code can be shortened? I can't see any reason for the dimensions you set at the beginning, so if you're just looking for shorter code, you could use the following:
With Selection.Find
.ClearFormatting
.Replacement.ClearFormatting
.Text = "([^s]{3})(normal)"
.Replacement.Text = "§§§\2"
.Forward = True
.Wrap = wdFindContinue
.Format = False
.MatchWildcards = True
.Execute Replace:=wdReplaceAll
.Forward = False
.ClearFormatting
.Replacement.Font.ColorIndex = wdBlue
.Format = True
.Text = "§§§"
.Replacement.Text = "1 "
.Execute Replace:=wdReplaceAll
End With
基于您具有这些尺寸的事实,并且您对其中一个尺寸使用了数字,我忍不住认为您实际上是在尝试创建一个编号系统,其中为每个实例赋予一个编号.如果是这样,那么您将使用以下代码:
Based on the fact that you have those dimensions, and you used a number for one of them, I can't help but think that you were actually trying to create a numbering system, where each instance is given a number. If that's the case, here's the code you would use:
Dim str_after, oldColor As String
Dim re_number As Integer
str_after = "normal"
re_number = "1"
Selection.HomeKey unit:=wdStory
With Selection.Find
.ClearFormatting
.Replacement.ClearFormatting
.Text = "([^s]{3})" & "(" & str_after & ")"
.Replacement.Text = "§§§\2"
.Forward = True
.Wrap = wdFindContinue
.Format = False
.MatchCase = False
.MatchWholeWord = False
.MatchAllWordForms = False
.MatchSoundsLike = False
.MatchWildcards = True
End With
While Selection.Find.Execute
oldColor = Selection.Font.Color
Selection.Font.Color = wdColorBlue
Selection.TypeText Text:=re_number & " "
Selection.Font.Color = oldColor
Selection.TypeText Text:=str_after
re_number = re_number + 1
Wend
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