排序多维数组? [英] Sorting a multidimensional array?
问题描述
我有一个看起来像这样的数组:
I have an array that looks like this:
Array ( [0] => Array ( [filters] => Array ( [filter_1] => 1
[filter_2] => 1
[filter_3] => 1
[filter_4] => 1
[filter_5] => 1
[filter_6] => 1 ),
[count] => 2),
[1] => Array ( [filters] => Array ( [filter_1] => 1
[filter_2] => 1
[filter_3] => 1
[filter_4] => 1
[filter_5] => 1
[filter_6] => 1 ),
[count] => 34)
[2] => Array ( [filters] => Array ( [filter_1] => 1
[filter_2] => 1
[filter_3] => 1
[filter_4] => 1
[filter_5] => 1
[filter_6] => 1 ),
[count] => 7)
是否可以通过每个[count]键对主数组键进行降序排序?因此它们的顺序如下:1 -2 -0
Is it possible to sort the main array keys by the [count] key in each, descending? So that they are in the following order: 1 -2 -0
推荐答案
您绝对希望 usort 函数.您可以定义排序功能如何确定较大还是较小.
You definitely want the usort function. You can define how the sort function determines which is larger or smaller.
如果可以正确地对每个子数组(过滤器"和计数")进行重新索引,那么这应该可以正常工作.通过重新索引,我的意思是新排序的数组将从0开始,逐渐增长到1,依此类推.除非您原来的数组是关联的,否则这几乎总是您想要的方式.
If it's alright that each sub-array (of "filters" and "count") gets re-indexed, this should work perfectly. By re-indexed, I mean the newly sorted array would start at 0, progress to 1, etc. This is almost always how you want it, unless your original array is associative.
例如:
usort($array, "byCount");
function byCount($a, $b)
{
if( $a['count'] == $b['count'] )
{
return 0;
}
return ($a['count'] < $b['count']) ? -1 : 1;
}
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