为什么该线程不起作用? [英] Why this thread doesn't work?
问题描述
我编写了这段代码来尝试在Android上运行线程,但是它不起作用.
I wrote this code to try threads on Android, but it doesn't work.
@Override
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.main);
Thread t = new Thread() {
@Override public void run() {
int i = 0;
while(true) {
i += 5;
if(i == 1000000)
break;
}
}
};
t.run();
}
我有一些GUI,当线程正常工作(i <1000000)时,GUI冻结.但是,当线程完成时(i == 1000000),一切正常. 怎么了?
I have some GUI and when thread works (i < 1000000), GUI freezes. But when thread is done (i == 1000000) everything works fine. What's wrong?
//对不起,我的英语
推荐答案
您正在调用t.run()
,这意味着您正在运行UI线程中的所有代码,而无需启动新线程.
You're calling t.run()
which means you're running all the code in the UI thread without starting a new thread.
您应该调用t.start()
,这将启动一个新线程并在该新线程内的run
方法中执行代码.
You should call t.start()
which will instead start a new thread and execute the code in the run
method within that new thread.
(我还建议实现Runnable
,然后将Runnable
传递给新的Thread
构造函数,而不是覆盖run
,这只是关注点分离的问题.它不会改变行为在这里,但这是对IMO的一种较清晰的思考方式.)
(I'd also recommend implementing Runnable
and then passing the Runnable
to a new Thread
constructor rather than overriding run
, just as a matter of separation of concerns. It won't change the behaviour here, but it's a cleaner way of thinking about it IMO.)
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