在Android上的Java的FOR循环中使用thread.start时，发生了threadthread.start已经启动的非法线程状态异常线程 [英] illegalthreadstateexception thread already started occurs when using thread.start in a FOR loop in Java on Android

问题描述

我正在使用一个FOR循环，该循环被设计为在每次迭代时再次启动线程.该线程用于从文本文件中提取数据.

I am using a FOR loop which has been designed to start the thread again on every iteration. The thread is used to extract data from text files.

该错误在第二次迭代中发生，错误为"illegalthreadstateexception线程已启动".我已经尝试过使用GetTopics.stop，即使它已被弃用，但尚未修复该错误.我还使用GetTopics.join来确保代码不会同时运行.

The error occurs on the second iteration where the error is "illegalthreadstateexception thread already started". I have tried using GetTopics.stop even though it has been deprecated but has not fixed the error. I also use GetTopics.join as a way of making sure the codes do not run simultaneously.

private void addTabs(ActionBar actionBar)
{
    ActionBar.Tab tab1=actionBar.newTab();
    tab1.setText("All");
    tab1.setTabListener(this);
    actionBar.addTab(tab1);


    for (addTabPosition = 2; addTabPosition < 11; addTabPosition++) {
        Thread GetTopics = new Thread();
        GetTopics.start();

        try {
            GetTopics.join();
        } catch (InterruptedException e) {
            // TODO Auto-generated catch block
            e.printStackTrace();
        }

        if(addTabMessage.contentEquals("FileNotFound")){
            Log.e("skiper", "file skiped" + addTabPosition);

    }else{

        switch (addTabPosition) {
        case 2:
            ActionBar.Tab tab2=actionBar.newTab();
            tab2.setText(addTabTitle);
            tab2.setTabListener(this);
            actionBar.addTab(tab2);
            break;
        case 3:
            ActionBar.Tab tab3=actionBar.newTab();
            tab3.setText(addTabTitle);
            tab3.setTabListener(this);
            actionBar.addTab(tab3);
            break;
        case 4:
            ActionBar.Tab tab4=actionBar.newTab();
            tab4.setText(addTabTitle);
            tab4.setTabListener(this);
            actionBar.addTab(tab4);
            break;
        case 5:
            ActionBar.Tab tab5=actionBar.newTab();
            tab5.setText(addTabTitle);
            tab5.setTabListener(this);
            actionBar.addTab(tab5);
            break;
        case 6:
            ActionBar.Tab tab6=actionBar.newTab();
            tab6.setText(addTabTitle);
            tab6.setTabListener(this);
            actionBar.addTab(tab6);
            break;
        case 7:
            ActionBar.Tab tab7=actionBar.newTab();
            tab7.setText(addTabTitle);
            tab7.setTabListener(this);
            actionBar.addTab(tab7);
            break;
        case 8:
            ActionBar.Tab tab8=actionBar.newTab();
            tab8.setText(addTabTitle);
            tab8.setTabListener(this);
            actionBar.addTab(tab8);
            break;
        case 9:
            ActionBar.Tab tab9=actionBar.newTab();
            tab9.setText(addTabTitle);
            tab9.setTabListener(this);
            actionBar.addTab(tab9);
            break;
        case 10:
            ActionBar.Tab tab10=actionBar.newTab();
            tab10.setText(addTabTitle);
            tab10.setTabListener(this);
            actionBar.addTab(tab10);
            break;

        }



    }
    }

}

推荐答案

首先关闭-一个线程不能运行两次.如果要并行运行2或再次运行它，则需要创建一个新的线程对象并运行它.

First off- a thread cannot be run twice. You need to create a new thread object and run it if you want to run 2 in parallel or run it again.

其次-如果您执行了thread.start后立即执行thread.join，则该线程毫无意义.我意识到这可能只是调试代码，但如果不是，则您在这里遇到一些体系结构问题.

Secondly- if you do a thread.start immediately followed by a thread.join, the thread is pointless. I realize this may just have been debug code, but if it isn't you have some architecture problems here.

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