SQL-从一个表中查找另一个表中不存在的记录 [英] SQL - find records from one table which don't exist in another

问题描述

我有以下两个SQL表(在MySQL中):

I've got the following two SQL tables (in MySQL):

Phone_book
+----+------+--------------+
| id | name | phone_number |
+----+------+--------------+
| 1  | John | 111111111111 |
+----+------+--------------+
| 2  | Jane | 222222222222 |
+----+------+--------------+

Call
+----+------+--------------+
| id | date | phone_number |
+----+------+--------------+
| 1  | 0945 | 111111111111 |
+----+------+--------------+
| 2  | 0950 | 222222222222 |
+----+------+--------------+
| 3  | 1045 | 333333333333 |
+----+------+--------------+

我如何找出phone_number不在Phone_book中的人拨打了哪些电话?所需的输出将是:

How do I find out which calls were made by people whose phone_number is not in the Phone_book? The desired output would be:

Call
+----+------+--------------+
| id | date | phone_number |
+----+------+--------------+
| 3  | 1045 | 333333333333 |
+----+------+--------------+

任何帮助将不胜感激.

推荐答案

执行查询的方法有多种，其效率各不相同，具体取决于查询优化器的性能以及两个表的相对大小:

There's several different ways of doing this, with varying efficiency, depending on how good your query optimiser is, and the relative size of your two tables:

这是最简短的陈述，如果您的电话簿很短，则可能是最快的陈述:

This is the shortest statement, and may be quickest if your phone book is very short:

SELECT  *
FROM    Call
WHERE   phone_number NOT IN (SELECT phone_number FROM Phone_book)

或者(由于 Alterlife )

SELECT *
FROM   Call
WHERE  NOT EXISTS
  (SELECT *
   FROM   Phone_book
   WHERE  Phone_book.phone_number = Call.phone_number)

或(感谢WOPR)

SELECT * 
FROM   Call
LEFT OUTER JOIN Phone_Book
  ON (Call.phone_number = Phone_book.phone_number)
  WHERE Phone_book.phone_number IS NULL

(忽略其他人所说的，通常最好只选择所需的列，而不是'*')

(ignoring that, as others have said, it's normally best to select just the columns you want, not '*')

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