显示错误消息PHP Mysql [英] Display error message PHP Mysql

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本文介绍了显示错误消息PHP Mysql的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

即使更新查询失败,我也无法使最后2个回波正常工作,但仍然显示成功.如果有人对此代码有任何建议要在任何行中进行改进,请这样做!

i am unable to get the last 2 echos to work, even if the update query fails it still displays success. If anyone has any suggestions on this code to be improved on any line, please do!

<?php
        if(!empty($_POST['username']) && !empty($_POST['answer']))  { 
            $username = $_POST['username'];
            $idfetch = mysql_query("SELECT id FROM users WHERE username ='$username'") //check it
            or die(mysql_error());
            $fetched = mysql_fetch_array($idfetch);  
            $id = $fetched['id']; //get users id for checking
            $answer = $_POST['answer'];
            $password = (mysql_real_escape_string($_POST['password']));
            $confpass = (mysql_real_escape_string($_POST['confpass']));
            if ($password != $confpass) {
                echo ("Passwords do not match, please try again.");
                exit;
            }
            $updatequery = mysql_query("UPDATE users SET PASSWORD='$password' WHERE id='$id' AND username='$username' AND answer='$answer'");
            if($updatequery)  {  
                echo "<h1>Success</h1>";  
                echo "<p>Your account password was successfully changed. Please <a href=\"login.php\">click here to login</a>.</p>";  
            }  
            else  {  
                echo "<h1>Error</h1>";  
                echo "<p>Sorry, but a field was incorrect.</p>";  
            }  
       } 
?>

提前谢谢!

推荐答案

mysql_query("UPDATE users SET PASSWORD='$password' WHERE id='$id' AND username='$username' AND answer='$answer'") or die(mysql_error()."update failed");

并使用

mysql_affected_rows()

Returns the number of affected rows on success, and -1 if the last query failed.

这篇关于显示错误消息PHP Mysql的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

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