同一张表中两个记录之间的日期差 [英] Date difference between two records in same table

问题描述

我有一个具有以下记录的表(job_logs): id，job_id，user_id，status，created_at，job_type.

I have a table (job_logs) with the following records: id, job_id, user_id, status, created_at, job_type.

每次作业开始运行记录时，都会用status='started'记录在job_log表中.当作业完成运行时，使用status='completed'将另一条记录添加到表中.

Each time a job starts to run a record is written in the job_log table with status='started'. When a job finish running another record is added to the table with status='completed'.

两个记录都具有相同的user_id，job_type和 job_id (由运行作业的进程确定-这两个记录是唯一的).

Both records has the same user_id, job_type and job_id (which is determined by the process running the job - unique to these 2 records).

我想要一个查询，该查询将返回表中的所有这些记录对(按ID desc排序)，但棘手的部分是我想将作业运行所花费的时间添加到已完成"状态的记录中(completed.created_at - started.created_at).

I want a query that will return all these records pairs in the table (ordered by id desc) but the tricky part is that I want to add to the record with the 'completed' status the time it took the job to run (completed.created_at - started.created_at).

我该怎么做?

推荐答案

SELECT j1.job_id AS job_id, (j2.created_at - j1.created_at) AS time_run
FROM job_logs j1 INNER JOIN job_logs j2 ON (j1.job_id = j2.job_id)
WHERE j1.status = 'started' AND j2.status = 'completed'

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