如果存在行或插入,则更新MySQL表的最快方法.超过2个非唯一键 [英] Fastest way to update a MySQL table if row exists else insert. More than 2 non-unique keys
本文介绍了如果存在行或插入,则更新MySQL表的最快方法.超过2个非唯一键的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我具有以下表格结构:
CREATE TABLE IF NOT EXISTS `reports` (
`id` int(11) NOT NULL AUTO_INCREMENT,
`day` int(11) NOT NULL,
`uid` int(11) NOT NULL,
`siteid` int(11) NOT NULL,
`cid` int(3) NOT NULL,
`visits` int(11) NOT NULL,
PRIMARY KEY (`id`)
)
目前,我正在检查&使用以下代码片段进行插入/更新:
Currently i check & insert/update with the following snippet:
$checkq = mysql_query("SELECT count(*) as rowexist FROM reports WHERE day='$day' AND uid='$uid' AND siteid='$sid' AND cid='$cid'") or die(mysql_error());
$checkr = mysql_fetch_array($checkq);
if ($checkr['rowexist'] > 0) {
mysql_query("UPDATE reports_adv SET visits=visits+1 WHERE day='$day' AND uid='$uid' AND siteid='$sid' AND cid='$cid'");
} else {
mysql_query("INSERT INTO reports_adv SET day='$day', uid='$uid', siteid='$sid', cid='$cid', visits='1'");
}
如果存在行,否则用超过2个非唯一键插入,这是更新此MySQL表的最快方法吗?
Is a fastest way to update this MySQL table if row exists else insert with more than 2 non-unique keys?
推荐答案
只需使用INSERT...ON DUPLICATE KEY UPDATE
INSERT INTO reports_adv (day, uid, siteid, cid, visits)
VALUES ('$day', '$uid', '$sid', '$cid', 1)
ON DUPLICATE KEY UPDATE visits=visits+1;
- 插入...在重复键更新语法上
- INSERT ... ON DUPLICATE KEY UPDATE Syntax
,但在进行其他操作之前,应在列上定义UNIQUE
约束.
but before anything else, you should define a UNIQUE
constraint on the columns.
ALTER TABLE reports_adv ADD CONSTRAINT tb_uq UNIQUE (day, uid, siteid, cid)
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