MySQL-使用SET语句的UPDATE查询取决于前一个SET语句的结果 [英] MySQL - UPDATE query with SET statement dependent on the outcome of the previous SET statement
问题描述
这是我想通过UPDATE语句实现的表格形式.
Here is a tabular representation of what I would like to achieve with an UPDATE statement.
+----+----+---+---+----+----------+---------------+---------------+
| ID | A | B | C | D | Calc A | Calc B | Calc C |
+----+----+---+---+----+----------+---------------+---------------+
| 1 | 6 | 5 | 2 | 10 | =[A]-[B] | =[Calc A]/[D] | =[B]/[Calc B] |
| 2 | 8 | 5 | 2 | 10 | =[A]-[B] | =[Calc A]/[D] | =[B]/[Calc B] |
| 3 | 10 | 5 | 2 | 10 | =[A]-[B] | =[Calc A]/[D] | =[B]/[Calc B] |
+----+----+---+---+----+----------+---------------+---------------+
我当前实现此目的的UPDATE语句如下...
My Current UPDATE statement to achieve this is as follows...
UPDATE [EXAMPLE]
SET [Calc A] = A - B
, [Calc B] = [Calc A] / D
, [Calc C] = B / [Calc B]
但是,它没有按预期运行. [Calc A]将在第一个UPDATE上正确计算.但是,[Calc B]将使用[Calc A]中的OLD值而不是我刚刚写入数据库的NEW更新值来进行计算.对于[Calc C]也是如此,它再次引用[Calc B]的OLD值.
However it is not working as intended. [Calc A] will calculate correctly on the first UPDATE. However [Calc B] will calculate using the OLD value in [Calc A] and not the NEW updated value I just wrote to the database. This holds true for [Calc C] which again refers to the OLD value of [Calc B].
如果执行UPDATE语句3次,则数据将正确计算出来.在第一次计算中正确设置了[计算A],然后,在第二次UPDATE中,[计算B]将引用正确的[计算A]更新值,然后,在计算中,[计算C]将参考正确的[计算B]值.第三次更新.
If you perform the UPDATE statement 3 times the data will calculate out correctly. [Calc A] is set correctly in the first calculation, then [Calc B] will reference the correct updated value of [Calc A] in the second UPDATE, then [Calc C] will reference the correct value of [Calc B] in the 3rd UPDATE.
所以我的问题是如何在ONE更新语句中将所有列设置为正确的值?
So my question is how do I set all the columns to their correct value in ONE update statement?
推荐答案
只需独立进行计算:
update [EXAMPLE]
set [Calc A] = A - B,
[Calc B] = (A - B) / D,
[Calc C] = B / ((A - B) / D)
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