多边形内的mysql查询点-没有结果 [英] mysql query points within polygon - no results
本文介绍了多边形内的mysql查询点-没有结果的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我很确定我在这里做错了很多事情,但是我不确定......
I'm pretty sure that I'm doing multiple things wrong here but I'm not sure what...
表(减去几个字段):
CREATE TABLE IF NOT EXISTS `stuff` (
`id` int(10) unsigned NOT NULL AUTO_INCREMENT,
`lat` decimal(12,7) NOT NULL,
`lon` decimal(12,7) NOT NULL,
`location` point NOT NULL,
UNIQUE KEY `id` (`id`),
KEY `distance` (`distance`),
KEY `lat` (`lat`),
KEY `lon` (`lon`),
SPATIAL KEY `location` (`location`)
) ENGINE=MyISAM DEFAULT CHARSET=utf8 COLLATE=utf8_unicode_ci AUTO_INCREMENT=5;
自动设置位置点的触发器:
The triggers to automatically set the location point:
DROP TRIGGER IF EXISTS `stuff_insert_defaults`;
DELIMITER //
CREATE TRIGGER `stuff_insert_defaults` BEFORE INSERT ON `stuff`
FOR EACH ROW SET NEW.location = PointFromText(CONCAT('POINT(',NEW.lat,' ',NEW.lon,')'))
//
DELIMITER ;
DROP TRIGGER IF EXISTS `stuff_update_location`;
DELIMITER //
CREATE TRIGGER `stuff_update_location` BEFORE UPDATE ON `stuff`
FOR EACH ROW SET NEW.location = PointFromText(CONCAT('POINT(',NEW.lat,' ',NEW.lon,')'))
//
DELIMITER ;
一些样本数据(科罗拉多州内的4个随机点):
Some sample data (4 random points within the state of Colorado):
/* 4 random points within the state of colorado */
INSERT INTO `stuff` (`id`, `distance`, `lat`, `lon`, `location`) VALUES
(1, 5.0000000, 40.2488450, -103.8003460, 0x000000000101000000f6622827da1f444001df6dde38f359c0),
(2, 5.0000000, 38.4849180, -107.8726700, 0x000000000101000000f19e03cb113e4340d28c45d3d9f75ac0),
(3, 5.0000000, 39.5040250, -105.3584800, 0x000000000101000000e6ae25e483c0434049111956f1565ac0),
(4, 5.0000000, 39.1904180, -106.8179680, 0x000000000101000000ed48f59d5f9843402b4b749659b45ac0);
科罗拉多州的粗略外边界:
The rough outter boundary of the state of Colorado:
NW corner: 41.000497 -109.050149
NE corner: 41.002380 -102.051881
SE corner: 36.993237 -102.041959
SW corner: 36.999037 -109.045220
查询应返回我们插入的4条记录:
The query which SHOULD return the 4 records we inserted:
SELECT *, AsText(location) FROM stuff
WHERE Contains(
GeomFromText('POLYGON((41.000497 -109.050149, 41.002380 -102.051881, 36.993237 -102.041959, 36.999037 -109.045220, 41.000497 -109.050149))'), location );
我要回来的东西...
What I'm getting back...
nada...
zip...
nil...
nothing...
推荐答案
如类Polygon
(添加了重点):
As documented under Class Polygon
(emphasis added):
Polygon
断言
Polygon
的边界由一组LinearRing
对象(即既是简单 又是封闭的 的LineString
对象)组成向上和向下延伸.
Polygon
Assertions
- The boundary of a
Polygon
consists of a set ofLinearRing
objects (that is,LineString
objects that are both simple and closed) that make up its exterior and interior boundaries.
因此,您必须通过在起点处完成来封闭多边形:
You must therefore close the polygon by finishing at the starting point:
SELECT *, AsText(location) FROM stuff
WHERE Contains(
GeomFromText('POLYGON((41.000497 -109.050149, 41.002380 -102.051881, 36.993237 -102.041959, 36.999037 -109.045220, 41.000497 -109.050149))'), location );
在 sqlfiddle 上查看.
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