PHP爆破数组以生成mysql IN条件 [英] PHP implode array to generate mysql IN criteria

问题描述

我具有如下功能:

public function foo ($cities = array('anaheim', 'baker', 'colfax') )
{
    $db = global instance of Zend_Db_Adapter_Pdo_Mysql...

    $query = 'SELECT name FROM user WHERE city IN ('.implode(',',$cities).')';
    $result = $db->fetchAll( $query );
}

这很好，直到有人将$ cities作为空数组传递为止.

This works out fine until someone passes $cities as an empty array.

为防止发生此错误，我一直在逻辑上使查询中断，如下所示:

To prevent this error I have been logic-breaking the query like so:

$query = 'SELECT name FROM user';
if (!empty($cities))
{
    $query .= ' WHERE city IN ('.implode(',',$cities).')';
}

但这不是很优雅.我觉得应该有一个更好的方法来按列表进行过滤，但是我不确定该如何做.有什么建议吗?

but this isn't very elegant. I feel like there should be a better way to filter by a list, but I am not sure how. Any advice?

推荐答案

至少使用quote方法...

if ($cities) {
    $query .= sprintf('WHERE city IN (%s)', implode(',', array_map(array($db, 'quote'), $cities)));
}   

或者，理想情况下，使用Zend_Db_Select ...构造查询.

or, ideally, construct the query with Zend_Db_Select...

$select = $db->select()->from('user', 'name');

if ($cities) {
  foreach ($cities as $city) {
        $select->orWhere('city = ?', $city);
    }
}

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