mysql查询中日期时间差的总和 [英] Sum of date time difference in a mysql query

问题描述

mysql表列是

Starttime - type:datetime, Stoptime - type:datetime

数据

Starttime, stoptime
2013-10-25 09:00:00, 2013-10-25 17:00:00
2013-10-26 09:00:00, 2013-10-26 17:00:00
2013-10-27 09:00:00, 2013-10-27 17:00:00
2013-10-28 09:00:00, 2013-10-28 17:45:00

查询

select, min(starttime), max(stoptime), 
SUM(TIME_TO_SEC(TIME_DIFF(stoptime - starttime))) total_hours from mytable

返回秒数，我可以使用TIME_TO_SEC()将其转换回时间...它以HH:MM:SS格式给出结果，例如28:45:00

returns a number of seconds which I can convert back to time using TIME_TO_SEC() ... it gives me result in the format HH:MM:SS e.g. 28:45:00

但是我需要将28:45:00转换为28.75小时格式.我该怎么办?

But I need to convert 28:45:00 into 28.75 hours format. How do I do that?

推荐答案

select, min(starttime), max(stoptime), 
SUM(TIME_TO_SEC(TIME_DIFF(stoptime - starttime))/3600) total_hours from mytable

这篇关于mysql查询中日期时间差的总和的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！