PHP bind_params为空 [英] PHP bind_params with null
问题描述
如果该变量存在,我试图将参数绑定到INSERT INTO MySQLi准备好的语句中,否则插入null.
I am trying to bind params to a INSERT INTO MySQLi prepared statement if that variable exists, otherwise insert null.
这是我所拥有的,但是不起作用:
This is what I have, but it is not working:
if (!empty($name)) {
$result->bind_param('ss', $name, $url_friendly_name);
} else {
$result->bind_param('ss', null, null);
}
if (!empty($description)) {
$result->bind_param('s', $description);
} else {
$result->bind_param('s', null);
}
有人知道这样做的更好方法吗,或者我的代码只是一个小问题.我正在对准备好的语句中的每个变量执行以上操作.
Does anyone know of a better way of doing this or is there just a minor issue with my code. I am doing the above for each variable in the prepared statement.
推荐答案
bind_param
通过引用起作用.这意味着它需要一个变量,然后使用execute
中该变量的值.
bind_param
works by reference. That means that it takes a variable, then uses the value of that variable in execute
.
null
不是变量.
尝试将变量设置为null
,然后绑定该变量.
Try setting a variable to null
and then binding that variable instead.
(也可以考虑使用PDO代替mysqli,其中execute
方法可以采用简单的数组,并且可以绕过mysqli的古怪绑定方法.)
(Also consider using PDO instead of mysqli, where the execute
method can take a simple array and you can bypass wacky binding methodology of mysqli.)
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