为什么会这样“如果"?语句被触发? [英] Why does this "if" statement get triggered?
问题描述
过去5个小时，我一直在努力研究为什么如果被触发...
I've been working for the past 5 hours on why does this if get triggered...
让我向您展示代码并向您解释:
Let me show you the code and explain you :
<?php
require_once "ConnectDB.php";
$link2 = $link;
$key = $posthwid = "";
$err = "";
if($_SERVER["REQUEST_METHOD"] == "POST"){
if(empty($_POST["key"])){
$err = "Thanks for the ip (" .$_SERVER['REMOTE_ADDR']. "), have a good day! (1)";
}
else{
$key = trim($_POST["key"]);
}
$hwid = $_POST["hwid"];
if(empty($err)){
$sql = "SELECT hwid, idkey, length, created_at FROM money WHERE idkey = '" .$key. "'";
$row = mysqli_query($link, $sql);
if(mysqli_num_rows($row) < 2){
while($result = mysqli_fetch_assoc($row)) {
if($result["idkey"] == $key)
{
$err = "key";
if($result["hwid"] == "")
{
$err = "nohwid";
$sql2 = "UPDATE IceCold SET hwid = '" .$hwid. "' WHERE idkey = '" .$key. "'";
if(mysqli_query($link2, $sql2)){
$hwid = $result["hwid"];
mysqli_close($link2);
echo "debug";
}
else {
$err = "Oops! Something went wrong. Contact the support.";
}
}
if ($hwid !== $result["hwid"]) {
$err = "Contact the support";
}
elseif($_SESSION["admin"] == true) {
//Do special stuff
}
else {
///do other checks
if($created_at > $date){
$err = $hwid;
} else {
$err = "The key date is too old, buy a new one.";
}
}
}
else{
$err = "The key you entered was not valid.";
}
} mysqli_close($link);
} else {
$err = "multiple entry, contact support";
}
}
} else {
$err = "Thanks for the ip (" .$_SERVER['REMOTE_ADDR']. "), have a good day! (3)";
}
echo $err;
?>
因此，基本上，我有一个名为$link的mysqli_connect连接数据库文件，并且正在为我的程序设计一个Liscence API.我的程序将发送一个带有"idkey"和"hwid"的请求，并且正在等待该hwid返回.我在sql数据库中有一个仅注册了密钥的条目，并且试图通过生成带有id和随机hwid的POST请求来使程序wotk出现，但未成功.如果怪异地移动变量，那是因为调试.
So basically, I have this Connect DB file with a mysqli_connect called $link and I'm designing a liscence API for my program. My program will send a request with the "idkey" and "hwid" and is waiting for the hwid to come back. I have an entry in my sql databse with only a key registered and I've trying to make my program wotk by generating POST request with the id and a random hwid but I've found no success. If variables are weirdly moved around, It's because of the debugging.
现在，在我当前的设置下，我得到了我不知道为什么?！"支持联系回复.如果我能够获得此遮篷，则请求和键是正确的. 这可能是一个愚蠢的错误，但我无法理解...
Right now, with my current setup, I get the Contact the support response which I don't understand why?!? The request and the key are correct if I'm able to get this awnser. It's probably a stupid mistake but I jsut can't figure it out...
预先感谢您的帮助
编辑:我要引用的if语句是这样的:
Edit: the if statement I'm referring to is this:
if($hwid !== $result["hwid"])
我修复的代码中有错别字，但这不是问题， 至于elseif，这将破坏代码的执行顺序并破坏其背后的逻辑(如果有道理的话).
There was a typo in the code that I fixed but it wasn't the issue, as for the elseif, that would destroy the order of execution of the code and destroy the logic behind it(If that made sense).
奇怪的是，经过一些测试，我发现我发送的第二个SQL请求不想执行($ sql2)，并且httpd日志中没有错误...您可以执行两个请求吗?我尝试创建$ link2，但它没有任何改变
Weirdly, after some tests, I found out that the second SQL request I send doesn't want to be executed ($sql2) and there is no error in httpd logs... Can you execute two requests? I tried to create $link2 but it doesn't change anything
EDIT :找到的解决方案
if($result["hwid"] == "")
{
$sql2 = "UPDATE money SET hwid = '" .$_POST["hwid"]. "' WHERE idkey = '" .$key. "'";
if(mysqli_query($link2, $sql2)) {
$newhwid = $_POST["hwid"];
mysqli_close($link2);
}
else {
$err = "Oops! Something went wrong. Contact the support.";
}
}
elseif ($_POST["hwid"] != $result["hwid"]) {
$err = "Contact the support";
}
if($_POST["hwid"] == $newhwid || $_POST["hwid"] == $result["hwid"] ) {
/// do other checks
}
推荐答案
该条件之前的条件if($row['hwid'] = "")是赋值.此代码将$row['hwid']的值更改为空字符串，导致其后的条件为true.我假设您打算在$row['hwid']为空的情况下将==写入 test .否则，将其写为if语句是没有意义的.
The condition before that one, if($row['hwid'] = ""), is an assignment. This code is changing the value of $row['hwid'] to an empty string, causing the condition after it to be true. I assume you meant to write == to test if $row['hwid'] is empty; otherwise it doesn't make sense to write this as an if statement.
顺便说一下，尚不清楚此if语句是否不应该是else if.这里的其余分支是else if(或elseif，在PHP中是相同的)，因此您应该考虑是否也错过了该分支上的else.
By the way, it's not clear whether this if statement shouldn't be an else if. The rest of the branches here are else if (or elseif, which is the same in PHP), so you should consider whether you have missed out an else on this one too.
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