从具有不同名称空间的类动态创建新对象 [英] Dynamically create a new object from a class with different namespace

问题描述

我正在尝试为我的数据库创建一个小的RESTful API，并且遇到了一个基于用户请求动态创建控制器对象的问题，因为我所有的代码都在使用命名空间并且只是在做:

I'm trying to create a small RESTful API for my database and I encountered a problem creating controller object dynamically based on user request, because all my code is using namespaces and just doing:

$api = new $controllerName($request);

不起作用.因为$controllerName会解析为"ReadController"，但实际上是\controllers\lottery\ReadController，因此会出现错误

Won't work. Because $controllerName would resolve to "ReadController", but is actually \controllers\lottery\ReadController hence the error

定义类路径的整个过程是:

The whole part of defining the path to the class is:

if ($method === 'GET') {
    $controllerName = 'ReadController';
    // @NOTE: $category is a part of $_GET parameters, e.g: /api/lottery <- lottery is a $category
    $controllerFile = CONTROLLERS.$category.'/'.$controllerName.'.php';
    if (file_exists($controllerFile)) {
        include_once($controllerFile);

        $api = new $controllerName($request);
    } else {
        throw new \Exception('Undefined controller');
    }
}

Core \ controllers \ lottery \ ReadController.php中的ReadController声明

And the declaration of ReadController in core\controllers\lottery\ReadController.php

namespace controllers\lottery;

class ReadController extends \core\API {

}

有什么想法可以动态创建对象吗?

Any ideas how to dynamically create the object?

谢谢！

推荐答案

$controllerName = 'controllers\lottery\ReadController';
new $controllerName($request);

从字符串实例化的类必须始终使用完全限定的类名.

Classes instantiated from strings must always use the fully qualified class name.

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