我如何编写使用badlogic框架，通过迭代数字打印的方法？ [英] How do I write a method using badlogic framework for iterating through the numbers to print?

问题描述

我一直在使用Mr.Nom框架从badlogic创建的游戏。我如何通过每个字符迭代并打印成绩吗？帮助。

I have created a game using Mr.Nom framework from badlogic. How do I iterate through each character and print the scores? Help.

推荐答案

尝试了这一点：使用一个单独的区域为所有的数字

try this out: Use a separate region for all the numbers

public void drawText(String line, float x, int y) {
    int len = line.length();
    batcher.beginBatch(Assets.numbers);
    for (int i = 0; i < len; i++) {
        char character = line.charAt(i);

        if (character == ' ') {
            x += 20;
            continue;
        }

        int srcX = 0;
        int srcWidth = 0;
        if (character == '.') {
            srcX = 200;
            srcWidth = 10;
        } else {
            srcX = (character - '0') * 20;
            srcWidth = 20;
        }


        if(character=='0')
            batcher.drawSprite(x, y, srcWidth, 32, Assets.zeroRegion);
        if(character=='1')
            batcher.drawSprite(x, y, srcWidth, 32, Assets.oneRegion);
     if(character=='2')
            batcher.drawSprite(x, y, srcWidth, 32, Assets.twoRegion);
         if(character=='3')
            batcher.drawSprite(x, y, srcWidth, 32, Assets.threeRegion);
         if(character=='4')
            batcher.drawSprite(x, y, srcWidth, 32, Assets.fourRegion);
         if(character=='5')
            batcher.drawSprite(x, y, srcWidth, 32, Assets.fiveRegion);
         if(character=='6')
            batcher.drawSprite(x, y, srcWidth, 32, Assets.sixRegion);
         if(character=='7')
            batcher.drawSprite(x, y, srcWidth, 32, Assets.sevenRegion);
         if(character=='8')
            batcher.drawSprite(x, y, srcWidth, 32, Assets.eightRegion);
         if(character=='9')
            batcher.drawSprite(x, y, srcWidth, 32, Assets.nineRegion);
         if(character=='.')
            batcher.drawSprite(x, y, srcWidth, 32, Assets.dotRegion);

        x += srcWidth;
    }
    batcher.endBatch();
}

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