Neo4j持久查询要拆分/执行成较小的块? [英] Neo4j long lasting query to be split/executed in smaller chunks?

查看:125
本文介绍了Neo4j持久查询要拆分/执行成较小的块?的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我的import.csv创建了许多节点,并且合并创建了一个巨大的笛卡尔积,并在transaction timeout中运行,因为数据增长了很多.我目前将事务超时设置为1秒,因为所有其他查询都非常快,并且完成时间不应超过一秒.

My import.csv creates many nodes and merging creates a huge cartesian product and runs in a transaction timeout since the data has grown so much. I've currently set the transaction timeout to 1 second because every other query is very quick and is not supposed to take any longer than one second to finish.

是否有一种方法可以将较小的块拆分或执行此特定查询,以防止超时?

Is there a way to split or execute this specific query in smaller chunks to prevent a timeout?

不能选择在neo4j.conf中添加或禁用transaction timeout,因为neo4j服务需要重新启动配置中的所有更改.

Upping or disabling the transaction timeout in the neo4j.conf is not an option because the neo4j service needs a restart for every change made in the config.

查询击中了我的导入脚本的超时时间:

The query hitting the timeout from my import script:

 MATCH (l:NameLabel)
 MATCH (m:Movie {id: l.id,somevalue: l.somevalue})
 MERGE (m)-[:LABEL {path: l.path}]->(l);

节点数:1000电影,2500名称标签

Nodecounts: 1000 Movie, 2500 Namelabel

推荐答案

您可以尝试安装 APOC程序,并使用过程 apoc.periodic.commit .

You can try installing APOC Procedures and using the procedure apoc.periodic.commit.

call apoc.periodic.commit("
  MATCH (l:Namelabel)
  WHERE NOT (l)-[:LABEL]->(:Movie)
  WITH l LIMIT {limit}
  MATCH (m:Movie {id: l.id,somevalue: l.somevalue})
  MERGE (m)-[:LABEL {path: l.path}]->(l)
  RETURN count(*)
",{limit:1000})

下面的查询将在单独的事务中重复执行,直到返回0.

The below query will be executed repeatedly in separate transactions until it returns 0.

您可以更改{limit : 1000}的值.

注意:请记住要根据所使用的Neo4j的版本安装APOC程序.看看版本兼容性列表..

这篇关于Neo4j持久查询要拆分/执行成较小的块?的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

查看全文
登录 关闭
扫码关注1秒登录
发送“验证码”获取 | 15天全站免登陆