使海龟根据列表中的排名顺序移动一次 [英] Make turtles move ONCE according to their ranked order in a list

问题描述

这个问题是基于我先前的问题2提出的.我一直在努力为自己的海龟按排名排序，并按自有因素进行排名.然后要求他们按排名顺序移动.该部分工作得很好，可以在以下位置找到代码:将乌龟分配给排名netlogo中的数字

This question is built off my previous 2. I've been working to get a rank-ordered list for my turtles, ranked by an owned factor. They're then required to move in ranked order. That part works perfectly fine, and the code can be found at: Assigning turtles a ranked number in netlogo

问题:使用该代码，它们以正确的顺序移动，而不是一次移动，该程序似乎在为列表中的每只乌龟连续不断地重新运行它，因此10只世界中的第一只乌龟结束了向上移动10次，第二次移动9次，等等.

The problem: using that code, they're moving in the correct order but instead of moving once, the program seems to be continuously re-running it for every turtle in the list so the first turtle in a world of 10 ends up moving 10 times, the second moves 9 times, etc.

我对此完全感到困惑，但是我需要停止它.他们应该移动一次，然后为该滴答作答.想法?

I'm completely stumped on this, but I need it to stop. They're supposed to move once and be done for that tick. Ideas?

列表创建代码为:

let rank-list sort-on [sociability] turtles
    let ranks n-values length rank-list [ ? ]  
   (foreach rank-list ranks [ask ?1 [set social_rank ?2] ] ) 
;;you can replicate the problem with this movement proc, or the full code in the link above       
 ask turtles [foreach rank-list [ask ? [set heading 270 forward 1]]]

推荐答案

在此行:

ask turtles [foreach rank-list [ask ? [set heading 270 forward 1]]]

您要让每只乌龟对rank-list中的每只乌龟执行命令.

You're asking each turtle to execute a command for each turtle in your rank-list.

只需删除ask turtles部分.

作为更一般的注释:foreach是列出ask对代理集的含义.它们都执行相同的基本操作，即对集合"的每个项目执行命令.代理集是唯一代理的无序集合.列表是可能重复的任何类型的项目的有序集合.

As a more general note: foreach is to lists what ask is to agentsets. They both do the same basic thing, which is to perform a command for each item of a "collection". Agentsets are unordered collections of unique agents. Lists are ordered collections of possibly duplicated items of any type.

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