为什么'\ n'==='\\ n'在php中为true? [英] Why is '\n' === '\\n' true in php?

问题描述

我了解:

'\n' // literally the backslash character followed by the character for lowercase n
"\n" // interpreted by php as the newline character

但是对于我的一生，我不明白为什么'\n' === '\\n'.在我看来，'\\n'等于三个单独的字符:两个单独的反斜杠，后跟字母n.

But for the life of me, I can't understand why '\n' === '\\n'. In my mind, '\\n' would equal three separate characters: two separate backslashes, followed by the letter n.

为什么'\n' === '\\n'在PHP中是true?

Why is '\n' === '\\n' true in PHP?

推荐答案

反斜杠仍然是单引号字符串中的转义字符(它对文字单引号进行转义).

The backslash is still an escape character in single-quoted strings (it escapes literal single quotes).

例如，这是非法的(因为反斜杠转义了右引号):

This is illegal for instance (since the backslash escapes the closing quote):

$path = 'C:\';

因此\\必须映射到文字反斜杠，以避免无意的转义.

So \\ must map to a literal backslash to avoid inadvertent escaping.

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