没有在我的XSLT中添加新行 [英] not adding new line in my XSLT

问题描述

我不确定为什么我的xslt不会在输出中添加新行... 这是我的xslt....

I am not certain why my xslt won't put a new line in my output... This is my xslt....

<?xml version="1.0" encoding="utf-8"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
    xmlns:msxsl="urn:schemas-microsoft-com:xslt" exclude-result-prefixes="msxsl"
>
  <xsl:output method="text" encoding="iso-8859-1"/>
  <xsl:variable name="newline"></xsl:variable>
  <xsl:template name="FairWarningTransform" match="/">    <!--@* | node()">-->

          <xsl:for-each select="//SelectFairWarningInformationResult">  

                <xsl:value-of select="ApplicationID"/>,<xsl:value-of select="USERID"/>
                &#10;
          </xsl:for-each>

        * Note.  This report outlines Fair warning entries into reported for the above time frame.

      </xsl:template>
</xsl:stylesheet>

这是我的输出...

1,TEST1,test2,

我希望它看起来像...

I want it to look like...

1,TEST
1,test2,

为什么不是这个角色 创建换行符

Why isn't this character creating a newline

推荐答案

XSLT的默认行为是忽略样式表中完全为空格的任何文本节点(即使某些空格被编码为类似于)，但保留<xsl:text>中的文本.

XSLT's default behavior is to ignore any text nodes in the stylesheet that are entirely whitespace (this is true even if some of the whitespace is encoded as entities like 
), except for text inside <xsl:text>, which is preserved.

我建议替换这些行:

<xsl:value-of select="ApplicationID"/>,<xsl:value-of select="USERID"/>
&#10;

与此:

<xsl:value-of select="concat(ApplicationID, ',', USERID, '&#10;')"/>

这样，应确保换行符包含在输出中.

That way the newline should be ensured to be included in the output.

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