如何在python nltk和wordnet中获取单词/同义词集的所有下位词? [英] How to get all the hyponyms of a word/synset in python nltk and wordnet?

问题描述

我现在有一个wordnet中所有名词的列表，现在我只想留下车辆中的单词并删除其余的单词.我该怎么做?下面是我要创建的伪代码，但我不知道如何使它工作

I have a list of all the nouns in wordnet now i want to leave only words which are vehicles and remove the rest. How do i do it? Below is the pseudo-code i want to make but i do not know how to make it work

for word in wordlist:
  if not "vehicle" in wn.synsets(word):
    wordlist.remove(word)

推荐答案

from nltk.corpus import wordnet as wn
vehicle = wn.synset('vehicle.n.01')
typesOfVehicles = list(set([w for s in vehicle.closure(lambda s:s.hyponyms()) for w in s.lemma_names()]))

这将为您提供来自每个同义词集的所有唯一词，它们是名词车辆"(第一感觉).

This will give you all the unique words from every synset that is a hyponym of the noun "vehicle" (1st sense).

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