numpy中的非重复随机数 [英] Non-repetitive random number in numpy

问题描述

如何在numpy中生成非重复的随机数?

How can I generate non-repetitive random numbers in numpy?

list = np.random.random_integers(20,size=(10))

推荐答案

numpy.random.Generator.choice offers a replace argument to sample without replacement:

from numpy.random import default_rng

rng = default_rng()
numbers = rng.choice(20, size=10, replace=False)

如果您使用的是1.17之前的NumPy，而没有Generator API，则可以使用

If you're on a pre-1.17 NumPy, without the Generator API, you can use random.sample() from the standard library:

print(random.sample(range(20), 10))

您还可以使用numpy.random.shuffle()和切片，但这会降低效率:

You can also use numpy.random.shuffle() and slicing, but this will be less efficient:

a = numpy.arange(20)
numpy.random.shuffle(a)
print a[:10]

在旧版numpy.random.choice函数中也有一个replace自变量，但是由于随机数流稳定性的保证，该自变量的实现效率很低，然后变得效率低下，因此不建议使用它. (基本上是在内部执行随机播放和切片操作.)

There's also a replace argument in the legacy numpy.random.choice function, but this argument was implemented inefficiently and then left inefficient due to random number stream stability guarantees, so its use isn't recommended. (It basically does the shuffle-and-slice thing internally.)

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