numpy.random函数中未知* [英] Unknown * in numpy.random function

问题描述

我正在研究此链接，这是代码.

I was studying this link and this is the code .

 U1 = np.random.rand(*H1.shape) < p # first dropout mask

为什么我尝试这样做会失败?

Why does it fail when I try to do this?

import numpy
numpy.random.rand(*1) < 2 

我知道rand()函数接受一个数字，这就是为什么我对代码应该起作用感到困惑的原因.

I understand that the rand() function takes in a number which is why I am confused that the code is supposed to work.

推荐答案

*将元组解包为多个输入参数.该代码使用shape属性(它是一个元组)作为np.random.rand的尺寸输入，创建与H1形状相同的随机矩阵.

The * unpacks a tuple into multiple input arguments. The code is creating a random matrix the same shape as H1 using the shape attribute (which is a tuple) as the dimension inputs to np.random.rand.

您可以使用任何元组执行此操作

You can do this with any tuple

np.random.rand(*(2,3))     # The same as np.random.rand(2,3)
# Creates a 2 x 3 array

您正试图解压缩将失败的整数.

You are trying to unpack an integer which is going to fail.

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