根据值是否在其他列表中而生成的numpy蒙版 [英] Numpy mask based on if a value is in some other list

问题描述

我已经搜索了高低档，却找不到解决方法(可能是我搜索了错误的字词.)

I have searched high and low and just cant find a way to do it (Its possible i was searching for the wrong terms.)

我想根据每个值是否在其他列表中来创建掩码(例如[True False False True True True]).

I would like to create a mask (eg [True False False True True]) based on whether each value is in some other list.

a=np.array([11,12,13,14,15,16,17])
mask= a in [14,16,8] #(this doesnt work at all!)
#I would like to see [False False False True False True False]

到目前为止，我能提出的最好的建议是列表理解

so far the best i can come up with is a list comprehension

mask = [True if x in other_list else False for x in my_numpy_array]

请让我知道您是否知道一些秘密的调味料可以快速地(以计算方式)执行此操作，因为实际上这个列表很大...

please let me know if you know of some secret sauce to do this with numpy and fast (Computationally), as this list in reality is huge...

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