self.ndim<时，numpy.ndarray.T和numpy.ndarray.transpose()有什么区别? 2个 [英] What's the difference of numpy.ndarray.T and numpy.ndarray.transpose() when self.ndim < 2

问题描述

文档 numpy. ndarray.T 说

ndarray.T —与self.transpose()相同，不同之处在于，如果self.ndim< 2.

ndarray.T — Same as self.transpose(), except that self is returned if self.ndim < 2.

此外，ndarray.transpose(* axes)表示

Also, ndarray.transpose(*axes) says

对于一维数组，这无效.

For a 1-D array, this has no effect.

这不是同一回事吗?

下面是一些演示代码段:

Here's a little demo snippet:

>>> import numpy as np
>>> print np.__version__
1.5.1rc1
>>> a = np.arange(7)
>>> print a, a.T, a.transpose()
[0 1 2 3 4 5 6] [0 1 2 3 4 5 6] [0 1 2 3 4 5 6]

推荐答案

不管排名如何，.T属性和.transpose()方法都是相同的-它们都返回数组的转置.

Regardless of rank, the .T attribute and the .transpose() method are the same—they both return the transpose of the array.

对于秩为1的数组，.T和.transpose()不执行任何操作-它们都返回数组.

In the case of a rank 1 array, the .T and .transpose() don't do anything—they both return the array.

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