如何将复数放入numpy的数组中? [英] How to put complex into a numpy's array?

问题描述

>>> import numpy as np
>>> A = np.zeros((3,3))
>>> A[0,0] = 9
>>> A
array([[ 9.,  0.,  0.],
       [ 0.,  0.,  0.],
       [ 0.,  0.,  0.]])
>>> A[0,1] = 1+2j
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
TypeError: can't convert complex to float
>>> A[0,1] = np.complex(1, 2)
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
TypeError: can't convert complex to float

根据我的示例代码.我试图将复数放入numpy的数组中，但是没有用.可能是我想念一些基本的东西.

According to my example code. i tried to put complex number into the numpy's array but it didn't work. May be i miss some basic thing.

推荐答案

如果要创建包含复杂值的数组，则需要为numpy指定复杂类型:

If you want to create an array containing complex values, you need to specify a complex type to numpy:

>>> A = np.zeros((3,3), dtype=np.complex)

>>> print A
[[ 0.+0.j  0.+0.j  0.+0.j]
 [ 0.+0.j  0.+0.j  0.+0.j]
 [ 0.+0.j  0.+0.j  0.+0.j]]

>>> A[0,0] = 1. + 2.j

>>> print A
[[ 1.+2.j  0.+0.j  0.+0.j]
 [ 0.+0.j  0.+0.j  0.+0.j]
 [ 0.+0.j  0.+0.j  0.+0.j]]

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