添加具有不同大小的二进制数组 [英] Adding binary arrays with different size

问题描述

我用数字及其每行的位长制成二进制数组，如果295289042101659每行6位，数字大小为49位，那么在数组中，它将是6位X 9行，通过代码并修改为6位长度零填充线:

I made binary arrays from number and its bit length per line, if 295289042101659 with 6 bits per line, number sizes 49 bit so in array, it would be 6 bits X 9 line, through the code and modified to 6-length zero filled lines:

def listify(a, bit = 5):
    res = []
    while a:
        a, b = divmod(a,2**bit)
        res.append(b)
    return res[::-1]

000001
000011
001001
000001
010110
011101
011110
010110
011011

000001
000011
001001
000001
010110
011101
011110
010110
011011

由于它是二进制数组，所以我使用了二进制加法代码而没有携带:

Since it is binary array, I used binary addition code without carrying:

def binaryadd(one, other):
    if one & other:
        return False
    return one | other

如果我得到一些大小为3的402(0b110010010)数组，那么如何通过上下坐标或在点(3,6)的上下坐标将其添加到点(2,2)处上，从右到左的坐标? 它应该看起来像是:

If I get some array of 402(0b110010010) with size 3, then how could I add into the array at point(2,2) by up-to-down coordinate, or (3,6) from down-to-up, right-to-left coordinate? It should be seemed as:

000001
00 11 11
001 1 01
000 1 01
010110
011101
011110
010110
011011

000001
001111
001101
000101
010110
011101
011110
010110
011011

我这样做是这样的:

def array_add(one,another, point = (0,0)):
    a = [a*2**point[0] for a in another[:]]
    a+=[0]*point[1]
    a = [0]*(len(one)-len(a))+a
    res = [binaryadd(a,b) for a, b in  zip(one[::-1],a[::-1])][::-1]
    if not all(res):
        return False
    return res

最好的方法是通过修改一个列表对列表的每个值应用二进制加法吗?

Is the best way to do it, is to apply binary addition to every values of list, by modifying one list?

还是我误解了数组的基础?

Or am I misunderstanding the basics of array?

推荐答案

由于您提到了numpy标签，因此可以使用它来具有高性能和可读代码:

Since you mention the numpy tag, you can use it to have high performance and readable code :

import numpy as np

def int_to_array(n,width):
    v=np.zeros(64,np.uint8)
    i,u,total=0,n,0
    while(u):
      if i%width == 0 : total += width  
      u,v[i],i = u//2,u%2,i+1
    return v[:total][::-1].reshape(-1,width)  

def add(a,b,point=(0,0)):
    sx,sy = point
    ex = sx+b.shape[0]
    ey = sy+b.shape[1]
    a[sx:ex,sy:ey] |= b

a=int_to_array(295289042101659,6)
b=int_to_array(402,3)
print(a)
print(b)
add(a,b,(2,2))   
print(a)

对于:

[[0 0 0 0 0 1]
 [0 0 0 0 1 1]
 [0 0 1 0 0 1]
 [0 0 0 0 0 1]
 [0 1 0 1 1 0]
 [0 1 1 1 0 1]
 [0 1 1 1 1 0]
 [0 1 0 1 1 0]
 [0 1 1 0 1 1]]

[[1 1 0]
 [0 1 0]
 [0 1 0]]

[[0 0 0 0 0 1]
 [0 0 0 0 1 1]
 [0 0 1 1 0 1]
 [0 0 0 1 0 1]
 [0 1 0 1 1 0]
 [0 1 1 1 0 1]
 [0 1 1 1 1 0]
 [0 1 0 1 1 0]
 [0 1 1 0 1 1]]

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