三个2D轮廓到3D阵列 [英] Three 2d profiles to 3d array

问题描述

在numpy中是否有可用的放样方法将三个2d轮廓转换为3d数组?其中x是直视视图，y是水平视图，z是鸟瞰视图.因此，如果在3d空间中x，y和z中的每个值都等于1，则保持值1，否则给出值0.因此，在这个小例子中，我应该相信有108个唯一值(9 * 12) ...

Is there a staking method available within numpy to convert three 2d profiles into a 3d array? Where x is the straight on view, y is the horizontal view and z is the birds eye view. Whereby if in a 3d space each value in the x,y and z are all equal to 1 maintain the value of 1 otherwise give a value of 0. So in this small example there should be 108 unique values I believe (9*12)...

import numpy as np

x = np.array([[1, 1, 1],
              [0, 1, 1],
              [0, 1, 1]])

y = np.array([[1, 1, 1],
             [ 1, 1, 1],
             [ 0, 1, 1],
             [ 0, 0, 1]])

z = np.array([[0, 1, 1],
             [ 0, 1, 1],
             [ 0, 0, 1],
             [ 0, 0, 0]])

即如果我们从[0, 0]的x数组开始，值是1，在位置y[0,0]处的值也是1，但是在z[0, 0]处的值也是0，因此在[0,0,0]处应为0.使用相同的位置x和y，但将z更改为位置z[0, 1]也是1的值，因此位置[0, 0, 1]的xyz 3d数组应为1.因此，应该从本质上讲是创建矩形3D网格的许多排列.

i.e. if we start from the x array at [0, 0] the value is 1, at position y[0,0] the value is also 1 however at z[0, 0] the value is 0 so the 3d array of xyz should be 0 at [0,0,0]. Using the same positions of x and y but changing z to position z[0, 1] is a value of 1 as well so the xyz 3d array at location [0, 0, 1] should be 1. So it should be a number of permutations essentially creating a rectangular 3D grid.

推荐答案

您可以结合广播和按位/逻辑运算来做到这一点:

You can combine broadcasting and bitwise/logical operations to do this:

>>> x[np.newaxis, :, :] & y[:, np.newaxis, :] & z[:, :, np.newaxis]
array([[[0, 0, 0],
        [0, 1, 1],
        [0, 1, 1]],

       [[0, 0, 0],
        [0, 1, 1],
        [0, 1, 1]],

       [[0, 0, 0],
        [0, 0, 0],
        [0, 1, 1]],

       [[0, 0, 0],
        [0, 0, 0],
        [0, 0, 0]]])
>>> 

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