NSString get-字符 [英] NSString get -characters

问题描述

我想获取一个NSString的字符.像这样:

I want to get the characters of an NSString. Like this:

NSString *data;
const char * typein = [[data characters] UTF8String];

但是显然NSString不会响应-字符.如何获取NSString的字符?

But obviously NSString won't respond to -characters. How do I get the characters of NSString?

谢谢， 以利亚

推荐答案

您可以使用此功能:

for(int i =0 ;i<[myString length]; i++) {
  char character = [myString characterAtIndex:i];
}

或

NSString *str = @"astring";
const char *cString = [str UTF8String];

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